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Maksim231197 [3]
3 years ago
7

A 3.00 g mass of compound x was added to 50.0 g of water and it is found that the freezing point has decreased by 1.25 degrees c

elcius. What is the molar mass of X if it has a van’t Hoff factor of 3?
Chemistry
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

yes

Explanation:

suck abbc

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What are the rules for writing
Alborosie

Answer:

When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” Mono-” indicates one, “Di-” indicates two, “Tri-” is three, “Tetra-” is four, “Penta-” is five, and “Hexa-” is six, “Hepta-” is seven, “Octo-” is eight, “Nona-” is nine, and “Deca-” is ten.

6 0
3 years ago
What happens to the speed of motion of the particles of a gas when a certain volume of the gas is heated at constant pressure? E
Likurg_2 [28]

Answer:

As the gas is heated, the particles will begin to move faster. ... Because the gas remains at a constant pressure and volume, the particles cannot spread out so they simply move around the container even faster.

4 0
3 years ago
Physostigmine, an alkaloid obtained from a West African plant (Physotigma venenosum),is used in the treatment of glaucoma. Treat
ozzi

Answer:

The structure of the salt is attached.

Explanation:

Physostigmine, an alkaloid obtained from a West African plant (Physotigma venenosum),is used in the treatment of glaucoma. Treatment of physostigmine with methyl iodide gives a quaternary ammonium salt. What is the structure of this salt?

The structure of the salt is attached

8 0
3 years ago
Butane, C4H10, is a component of natural gas that is used as fuel for cigarette lighters. The balanced equation of the complete
zavuch27 [327]

Answer:

So the volume will be 2.33 L

Explanation:

The reaction for the combustion is:

2 C₄H₁₀ (g) + 13 O₂ (g) → 8 CO₂ (g) + 10 H₂O (l)

mass of butane to moles (mass / molar mass)

1.4 g / 58 g/mol

= 0.024 moles

2 moles of butane can produce 8 moles of carbon dioxide

0.024 moles of butane must produce (0.024 × 8) /2

= 0.096 moles of CO₂

Now we apply the Ideal Gases Law to find out the volume formed.

P . V = n . R . T

p = 1atm

n = 0.096 mol

R = 0.082 L.atm/mol.K

T = 273 + 23 = 296K

V = ?

1atm × V = 0.096 mol × 0.082 L.atm/mol.K × 296K

V = 0.096 mol × 0.082 L.atm/mol.K × 296K / 1atm

= 2.33 L

So the volume will be 2.33 L

5 0
3 years ago
Read 2 more answers
How many grams are in 2.3 x 10-4 moles of calcium phosphate,<br> Ca3(PO3)2?
scZoUnD [109]

Answer:

7136900g or 7136 kg

 

Explanation:

5 0
3 years ago
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