H2(g) +C2H4(g)→C2H6(g)
H-H +H2C =CH2→H3C-Ch3
2C -H bonds and one C-C bond are formed while enthalpy change (dH) of the reaction,
H-H: 432kJ/mol
C=C: 614kJ/mol
C-C: 413 kJ/mol
C-C: 347 kJ/mol
dH is equal to sum of the energies released during the formation of new bonds or negative sign, and sum of energies required to break old bonds or positive sign.
The bond which breaks energy is positive.
432+614 =1046kJ/mol
Formation of bond energy is negative
2(413) + 347 = 1173 kJ/mol
dH reaction is -1173 + 1046 =-127kJ/mol
P=18000000/6 zeros. not sure how to do rest
Answer:
The Bohr model show the protons in a carbon atom using the model; "Electrons move in fixed orbits around a nucleus of protons and neutrons."
According to Bohr's model of the atoms, the Rutherford model is basically correct. This implies that Bohr model accepts the idea of a nucleus containing nucleons(protons and neutrons).
In addition, the model also postulates that electrons are found in fixed orbits. These fixed orbits are called energy levels or shells.
A graphic description of this is shown in the image attached to this answer.
Learn more: brainly.com/question/3964366
Explanation:
Answer:
up down up down thats the pattern
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