A because I did the math and that’s what it is for I 1/2
Yo im sorry but I can’t help I’m jus trying to answer questions so I can ask them
The lengths of pregnancies are normally distributed with a mean of 266 days and a standard deviation of 15 days.
That is,
Consider X be the length of the pregnancy
Mean and standard deviation of the length of the pregnancy.
Mean 
Standard deviation \sigma =15
For part (a) , to find the probability of a pregnancy lasting 308 days or longer:
That is, to find 
Using normal distribution,



Thus 
So 




Thus the probability of a pregnancy lasting 308 days or longer is given by 0.00256.
This the answer for part(a): 0.00256
For part(b), to find the length that separates premature babies from those who are not premature.
Given that the length of pregnancy is in the lowest 3%.
The z-value for the lowest of 3% is -1.8808
Then 
This implies 
Thus the babies who are born on or before 238 days are considered to be premature.
Answer:
5,7,-1
Step-by-step explanation:
5) -5+5<7=0<7 TRUE
7)-7+5<7=--2<7 TRUE
-1)-(-1)+5<7=6<7 TRUE
-3)-(-3)+5<7=8<7 FALSE
-2)-(-2)+5<7=7<7 FALSE
For this one I would add the measurements for the 3 shins and subtract it from 1.2.
0.125 + .09 + .75 = .965
Then...
1.20 - .965= .235
So...
The fourth board has the width of .235 cm.