Answer: B: 24q+48r
Step-by-step explanation: 6(4q+8r)
=(6)(4q+8r)
=(6)(4q)+(6)(8r)
=24q+48r
2x^2 + 14x + 12 = 0
x^2 + 7x + 6 = 0
( x + 1 )( x + 6 ) = 0 ==》 x = - 1 Or x = - 6
Answer:
Angle of elevation from Kim to the satellite launch = 6.654°
Step-by-step explanation:
The distance from Kim to the satellite launch
= 6 miles
Height of the satellite launch
= 0.7 miles
Angle of elevation from Kim to the satellite launch = b
Tan b = height of satellite/distance from Kim
Tan b= 0.7/6
Tan b= 0.1166667
b = tan^-1 (0.1166667)
b= 6.654°
Angle of elevation from Kim to the satellite launch = 6.654°
I am not sure about the formula but if you subtract 8,884 from 10,712 you get 1,828. Then, if you divide that by 4 you get 457. 457 fph(feet per hour) should be the climbers vertical speed.