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2 years ago

Which circuit prevents the flow of current?

2 answers:

5 0

The answer is Open Circuit. Open Circuit is a circuit that has a break that prevents the flow of current; a circuit with a gap that stops the current. An "open" (off) switch leave gaps in a circuit preventing electrons from traveling from one side of the power source to the other. Thus, electrons will not flow. This situation is called an open circuit.

Amanda [17]2 years ago

3 0

Answer:

" OPENN"

Explanation:

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A hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 4.0 m/s, skat

Cerrena [4.2K]

Answer:

a) $t=59.817652833125294s \approx 59.8s$

b) $D_1=894.01m$

Explanation:

From the question we are told that

Speed of opposing player $V_2=4.0m/s$

First player chase his opponent after $t=2.80t$

Acceleration of first player $a=0.14 m/s2$

Let time of catch be $t_c$

a)Generally the Equation for distance covered is mathematically given as follows

Distance to catch First opponent

$D_1=\frac{1}{2}(0.14)t^2$

$D_1=0.07t^2$

Distance to covered Second opponent

$D_2=(2.8+t)*4$

Generally when first opponent catch the second opponent it is represented mathematically as

$D_2=D_1$

$0.07t^2=(2.8+t)*4$

$0.07t^2=11.2+4t$

$0.07t^2-4t-11.2$

$t=59.817652833125294s \approx 59.8s$

b)Generally the the total time traveled by the first opponent is mathematically given as

$D_1=\frac{t^2}{4}$

$D_1=\frac{59.8^2}{4}$

$D_1=894.01m$

3 0

3 years ago

Which has more momentum? A paper airplane with a mass of 10g flying at a velocity of 4m/s or a real airplane that is parked at a

vladimir1956 [14]

The momentum is calculated by multiplying the mass and the velocity of the object.
momentum 1 : = (10 g)(4 m/s) = 40 g m/s
momentum 2: = (1000 kg)(0 m/s) = 0 kg m/s
Thus, the paper airplane has a greater momentum than the real airplane.

5 0

3 years ago

A rod 10.0 cm long is uniformly charged and has a total charge of -21.0 µC. Determine the magnitude and direction of the electri

lesya692 [45]

Answer:

The magnitude of electric field is $2.3\times10^6\ C/m^2$ and the direction is inward.

Explanation:

Given that,

Length of rod = 10.0 cm

Charge $Q = -21.0\times10^{-6}\ C$

Distance D = (34.0-10) cm = 0.24 m

We need to calculate the electric field along the axis

$E=\dfrac{kQ}{D(D+L)}$

Where, Q = charge

D = distance

Put the value into the formula

$E = \dfrac{9\times10^{9}\times(-21\times10^{-6}}{0.24(0.24+0.10)}$

$E=-2.3\times10^6\ C/m^2$

Negative sign shows the direction of electric field is inward that means toward the center.

Hence, The magnitude of electric field is $2.3\times10^6\ C/m^2$ and the direction is inward.

6 0

3 years ago

A toboggan approaches a snowy hill moving at 11.7 m/s. The coefficients of static and kinetic friction between the snow and the

soldi70 [24.7K]

Answer:

The acceleration of the toboggan going up and down the hill is 8.85 m/s² and 3.74 m/s².

Explanation:

Given that,

Speed = 11.7 m/s

Coefficients of static friction = 0.48

Coefficients of kinetic friction = 0.34

Angle = 40.0°

(a). When the toboggan moves up hill, then

We need to calculate the acceleration

Using formula of acceleration

$a=g(\sin\theta+\mu_{k}\cos\theta)$

Put the value into the formula

$a=9.8(\sin40+0.34\times\cos40)$

$a=8.85\ m/s^2$

(b). When the toboggan moves up hill, then

We need to calculate the acceleration

Using formula of acceleration

$a=g(\sin\theta-\mu_{k}\cos\theta)$

Put the value into the formula

$a=9.8(\sin40-0.34\times\cos40)$

$a=3.74\ m/s^2$

Hence, The acceleration of the toboggan going up and down the hill is 8.85 m/s² and 3.74 m/s².

5 0

3 years ago

Is it possible for two different objects to have the same velocity but at different speeds?

Papessa [141]

No. since velocity is speed given in direction. TO HAVE identical velocity, the OBJECT must be going in the same direction, and have the same speed.

also, objects can have the same speed and different velocity, if they travel in non-identical directions.

4 0

3 years ago