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2 years ago

Determine the domain and range of F(x)=2(x+1)^2-3

Mathematics

2 answers:

alexdok [17]2 years ago

6 0

Domain is 0
range is -1

ollegr [7]2 years ago

3 0

Answer: domain: all real numbers. range: [-3, infinity)

Step-by-step explanation:

We've got $f(x) = 2(x+1)^2 - 3$ .

You can plug in any number for $x$ without a problem, so the domain is all real numbers, written $\mathbb R$ .

If you graph the function, you can see it touches -3 but cannot go lower; however, it can reach anything higher than -3. Therefore the range is $[-3, \infty)$ .

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Janice's insurance costs $1,245 a year. How much should she budget for insurance each month? *

Phoenix [80]

Answer:

$103.75

Step-by-step explanation:

$1,245 devide by 12

5 0

2 years ago

78 correct answers out of 100 test questions and 39 correct answers out of 50 question are these equivalent

storchak [24]

78/100
= 39/50

39/50
= 39/50

yes these is equivalent

3 0

2 years ago

Read 2 more answers

If y= -7 when x= -28, find y when x=20

weqwewe [10]

This question is imposible in the field of math because, you need two points in order to determine slope and you only have one which is (-28, -7) which isn’t enough

5 0

3 years ago

A rectangular piece of cardboard measuring

MariettaO [177]

Answer:

(a) x<8

(b) $\displaystyle v=384x-80x^2+4x^3$

(d) $\displaystyle 0.917$

Step-by-step explanation:

<u>Optimization </u>

It is the procedure to find the set of values for the variables of a function such that it reaches a maximum or a minimum value. If equalities are given as relationships between the variables, then the derivative is a suitable method to find the critical points or candidates for extrema values.

The problem at hand is about a geometric maximization, given some dimensional conditions. First, we have a rectangular piece of cardboard measuring 24 x 16 inches. A box is to be made out of that cardboard by cutting equal size squares from each corner and folding up the sides of length x.

(a)

$\displaystyle w=24\ in$

$\displaystyle L=16\ in$

When we do so, the base of the box will have dimensions

$\displaystyle W'=24-2x$

$\displaystyle L'=16-2x$

Since the new width of the base must be positive, then

$\displaystyle 24-2x>0$

which poses the restriction

$\displaystyle x$

The same situation happens with the length

$\displaystyle 16-2x>0$

x<8

Since this last condition is more restrictive than the first, we state that x must be less than 8

(b) The volume of the box is the product of the area of the base by the height x

$\displaystyle v=L'.W'.x$

$\displaystyle v=(16-2x)(24-2x)\ x$

Operating

$\displaystyle v=(384-80x+4x^2)x$

$\displaystyle v=384x-80x^2+4x^3$

(c)

To find the maximum volume, we take the first derivative of V:

$\displaystyle v'=384-160x+12x^2$

Equating to zero to find the critical points

$\displaystyle v'=0$

$\displaystyle 12x^2-160x+384=0$

Dividing by 4:

$\displaystyle 3x^2-40x+96=0$

The roots of the equation are:

$\displaystyle x=10.19,x=3.13$

Since x=10.19 is out of the restrictions found in part a, the only valid solution is

$\displaystyle x=3.13$

We must test if the critical point is a maximum or a minimum, by computing the second derivative

$\displaystyle v''(x)=-160+24x$

$\displaystyle v''(3.13)$

Since the second derivative is negative, the value is a maximum

(d) We must find all the values of x such as v>288:

$\displaystyle 384x-80x^2+4x^3>288$

Rearranging

$\displaystyle 4x^3-80x^2+384x-288>0$

Simplifying by 4

$\displaystyle x^3-20x^2+96x-72>0$

Factoring

$\displaystyle (x-6)(x^2-14x+12)>0$

$\displaystyle (x-6)(x-13.083)(x-0.917)>0$

We found three real and positive roots for the third-degree polynomial

$x=6,\ x=0.917,\ x=13.083$

The function is positive when

$\displaystyle 0.917$

$\displaystyle x>13.083$

The only interval lying into the valid values of x is

$\displaystyle 0.917$

5 0

3 years ago

UVWX is a parallelogram.<br> Given WV=x+8 and XU=2x+3, find the value of x.

Rudik [331]

Answer:

x = 5

Step-by-step explanation:

If you draw out the parallelogram UVWX, WV is across from XU, meaning they're congruent because opposite sides of a parallelogram are congruent.

So:

x + 8 = 2x + 3

8 = x + 3

5 = x

x = 5

3 0

3 years ago