Determine the domain and range of F(x)=2(x+1)^2-3

Mathematics

2 answers:

alexdok [17]2 years ago

6 0

Domain is 0
range is -1

ollegr [7]2 years ago

3 0

Answer: domain: all real numbers. range: [-3, infinity)

Step-by-step explanation:

We've got $f(x) = 2(x+1)^2 - 3$ .

You can plug in any number for $x$ without a problem, so the domain is all real numbers, written $\mathbb R$ .

If you graph the function, you can see it touches -3 but cannot go lower; however, it can reach anything higher than -3. Therefore the range is $[-3, \infty)$ .

You might be interested in

Step 2: Radii OK and NL are perpendicular to OM because of the radius-tangent theorem. By definition of perpendicular, angles KO

viva [34]

Answer:

<h2>AAA postulate.</h2>

Step-by-step explanation:

Givens

Angles KOM and LNM are congruent, because both are right.
Angle LNM is common to both triangles.

If two internal angles of two triangles are congruent, then the third angle is also congruent.

Therefore, the similarity is proven by AAA postulate, which states that if we have three corresponding angles congruent, then those triangles are similar.

Remember that similarity is about proportion between sides and congruence between angles.

8 0

2 years ago

AHHHHHHHHHHHHHHH SOMEONE ANSWEER THIS PLEEASEEE NEED ANSWER ASP 20 pts!! Please answer!!! I literally don't get this ;c so PLEAS

Blababa [14]

Answer:

$P(A\textrm{ and }B)=\frac{3}{14}$