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soldi70 [24.7K]
3 years ago
8

At a movie theater, tickets for children cost $8 each and adult tickets cost $8.75 each. Of ticket sales for a group of 35 peopl

e totaled $259, how many children were in this group?
Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0

Answer:

The results don't make sense

Step-by-step explanation:

We can solve by means of a 2x2 system of equations, we have to:

"x" is the number of children's tickets

"y" is the number of adult tickets

Thus:

8 * x + 8.75 * y = 259

 x + y = 35 => x = 35 - y

replacing we have:

 8 * (35 - y) + 8.75 * y = 259

280 - 8 * y + 8.75 * y = 259

 - 8 * y + 8.75 * y = 259 - 280

0.75 * y = -21

y = -21 / 0.75

y = -28

Thus:

x = 35 - (-28) = 63

With these results we notice that the problem has inconsistency, since the value of the tickets cannot be given a negative number, I recommend reviewing the problem, since the approach is correct.

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Answer:

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Solve for k over the real numbers:

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(2 (2 k^2 - 5))/k = 8

Multiply both sides by k:

2 (2 k^2 - 5) = 8 k

Expand out terms of the left hand side:

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Subtract 8 k from both sides:

4 k^2 - 8 k - 10 = 0

Divide both sides by 4:

k^2 - 2 k - 5/2 = 0

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