The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Answer:
Happy Thanksgiving, my friends.
Step-by-step explanation:
C. 224
10x8=80, 80/2=40, 40x4(all triangles)=160
8x8(square)=64
160+64=224
Answer:
Answer B, AB is parallel to CD
Step-by-step explanation:
I'm 99% sure this is the answer.
The length is 20 ft. 10ft times 20ft = 200ft^2