
first let's name a couples of variable
• the number of adults tickets sold: a
• the number of children tickets sold: c
From the problem we know
a + c = 128
and
$5.40c + $9.20a = $976.20
1) solve the equation to alpha
a+c-c = 128 -c
a+0=128-c
a=128-c
2) substitute (128 - c) for a in the second equation and solve to c
$5.40c + $9.20a = $976.20 become
$5.40c + $9.20(128 - c) = $976.20
$5.40c + ($9.20 × 128) - ($9.20 - c) = $976.20
$5.40c - $9.20c + $ 1177.6 = $976.20
($5.40 - $9.20)c +$1177.6 = $976.20
-$3.80c + $1177.6 = $9.76.20
-$3.80c + $1177.60 - $1177.60 = $976.20 - $1177.60
-$8.30c + 0 = $201.40
-$3.80c = - $201.40
-$3.80c. -$201.40
________. = _________
-$3.80. -$3.80
-$3.80c. -$201.40
________. = _________. - they are 4 cut the no
-$3.80. -$3.80
c = $201.40
________
3.80
c = 53
Answer:
The answer is the last one.
Step-by-step explanation:
Firstly, look at the first inequality and we get
, so
. In the second inequality, we have
, so
. Together, we know that the answer is the last one.
Answer:
at least $1,050,000
Step-by-step explanation:
Deandre's salary will be ...
12000 + 0.06·sales
He wants that to be at least 75000, so the sales must meet the requirement ...
12000 + 0.06·sales ≥ 75000
0.06·sales ≥ 63000 . . . . . . . . . . . . subtract 12000
sales ≥ 63000/0.06 . . . . . . . . . . . .divide by 0.06
sales ≥ 1,050,000 . . . . . . . . . . . . . .evaluate
He will need to have at least $1,050,000 in total sales to have a yearly income at least $75,000.
Answer:
The student's z-score will not change
Explanation:
Z-scores are used to compare results of an individual or entity to the average population's scores.
Since the adjustment of additional points is added to each class member's score, the adjustment will shift the entire distribution of scores. However, there will not be a change in the relative position of the student's score in the class. As a result, the student's z-score will not change.
Answer:
4=m4-1
Step-by-step explanation:
This is because you're using gas so you're slope of the equation will have to be negative. If correct please mark brainliest. thx