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Sliva [168]
3 years ago
13

Susie has a genotype of blue eyes (bb) and her husband Jim has brown eyes dominant (BB). What is the likelihood (percentage) the

ir kid will have brown or blue eyes?
Biology
1 answer:
Arlecino [84]3 years ago
7 0

Answer:

The kid would possibly have the eye color from a family member. Also it could be ether one. And it could be none. My little brothers eyes are hazel but the mother and father of me and my brother eye color are different the father's eye color is brown and the mother's eye color is blue. But the little brother's eye color is hazel. So it could be none.

Explanation:

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In a population of Mendel's garden peas, the frequency of the dominant A (yellow flower) allele is 80%. Let p represent the freq
DENIUS [597]

Answer:

If the frequency of the dominant allele in the pea population is 0.8, the genotype frequencies in the population would be 0.64 AA, 0.32 Aa, and 0.04 aa.

Explanation:

Hardy-Weinberg equation tells us that:

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p2 is the frequency of AA plants

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A allele in the population is 80%, the frequency is 0.8.

p represent the frequency of A allele. p is 0.8

Therefore calculating for q ( frequency of a allele).

p + q = 1.0

q = 1.0 − p

q = 1.0 − 0.8

q = 0.2

p = 0.8, q = 0.2.

Now we can calculate the predicted frequencies of the different genotypes, remembering that p2 is the frequency of the AA genotype, 2pq is the frequency of the Aa genotype, and q2 the frequency of aa genotype.

p2 = 0.8 x 0.8 = 0.64

2pq = 2 x 0.8 x 0.2 = 0.32

q2 = 0.2 x 0.2 = 0.04.

Thus, we would expect to see genotype frequencies of 0.64 AA, 0.32 Aa, and 0.04 aa in the pea plants.

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