D because if you multiply y 8 times it will no longer be doubling the area
Answer:
i hope this helps :) i answered the other one but they deleted it
Step-by-step explanation:
bottom left = 55
middle = 75
right = 56
top should be 79

Euclid's division lemma : Let a and b are two positive integers. There exist unique integers q and r such that
a = bq + r, 0
r < b
Or We can write it as,
Dividend = Divisor × Quotient + Remainder
<u>Work</u><u> </u><u>out</u><u>:</u>
Given integers are 240 and 228. Clearly 240 > 228. Applying Euclid's division lemma to 240 and 228,
⇛ 240 = 228 × 1 + 12
Since, the remainder 12 ≠ 0. So, we apply the division dilemma to the division 228 and remainder 12,
⇛ 228 = 12 × 19 + 0
The remainder at this stage is 0. So, the divider at this stage or the remainder at the previous age i.e 12

<u>━━━━━━━━━━━━━━━━━━━━</u>
C. The vertexes are the same. The functions' vertex (h,k) values were not altered, just a (stretch/compress).
Answer:
B
Step-by-step explanation: