From the given figure ,
RECA is a quadrilateral
RC divides it into two parts
From the triangles , ∆REC and ∆RAC
RE = RA (Given)
angle CRE = angle CRA (Given)
RC = RC (Common side)
Therefore, ∆REC is Congruent to ∆RAC
∆REC =~ ∆RAC by SAS Property
⇛CE = CA (Congruent parts in a congruent triangles)
Hence , Proved
<em>Additional</em><em> comment</em><em>:</em><em>-</em>
SAS property:-
"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)
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Answer:
Answer is 6(3 d+2)
Step-by-step explanation:
It is given the expression as 18d+12
Let's find common factor by prime factoring the terms.
18 d =2*3*3*d
12= 2*2*3
Common factors for both terms are 2, 3.
So, G C F = 2*3=6
Take out 6 from both terms to factor further.
We do get 6(3 d+2)