What are three ways to write the number 24? Please help!!!!!!

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

6 0

24, 12x2, 6x4, and 48/2

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The volume of this prism is 4375cm3.<br> The area of the cross-section is 125cm2.<br> Work out x

fomenos

Answer:

x is 35 cm

Step-by-step explanation:

To find the value of x, we will divide the volume by the cross-section

Mathematically, that will be;

4375/125 = 35 cm

5 0

2 years ago

Determine the first five iterates of f(x)=1.5x(1-x) for x0=0.8

kherson [118]

<span>f(x) = 1.5 x (1 - x)
f(0.8) = 1.5(0.8)(1 - 0.8) = 0.24
f(0.24) = 1.5(0.24)(1 - 0.24) ~= 0.274
f(0.274) = 1.5(0.274)(1 - 0.274) ~= 0.298
f(0.298) = 1.5(0.298)(1 - 0.298) ~= 0.314
f(0.314) = 1.5(0.314)(1 - 0.314) ~= 0.323

</span>So the answer is D : 0.24, 0.274, 0.298, 0.314, 0.323

3 0

3 years ago

Simplify the expression.

Marizza181 [45]

$\bf \textit{Cofunction Identities}
\\ \quad \\
sin\left(\frac{\pi}{2}-{{ \theta}}\right)=cos({{ \theta}})\qquad 
\boxed{cos\left(\frac{\pi}{2}-{{ \theta}}\right)=sin({{ \theta}})}
\\ \quad \\ \quad \\
tan\left(\frac{\pi}{2}-{{ \theta}}\right)=cot({{ \theta}})\qquad 
cot\left(\frac{\pi}{2}-{{ \theta}}\right)=tan({{ \theta}})
\\ \quad \\ \quad \\
sec\left(\frac{\pi}{2}-{{ \theta}}\right)=csc({{ \theta}})\qquad 
csc\left(\frac{\pi}{2}-{{ \theta}}\right)=sec({{ \theta}})$

$\bf \\\\
-------------------------------\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta )
\\\\\\
\boxed{cos(\theta )=\sqrt{1-sin^2(\theta )}}$

$\bf \\\\
-------------------------------\\\\
\cfrac{cos^2\left(\frac{\pi }{2}-x \right)}{\sqrt{1-sin^2(x)}}\implies \cfrac{\left[ cos\left(\frac{\pi }{2}-x \right)\right]^2}{cos(x)}\implies \cfrac{[sin(x)]^2}{cos(x)}\implies \cfrac{sin(x)sin(x)}{cos(x)}
\\\\\\
sin(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)tan(x)$

6 0

3 years ago

A 13-foot ladder leans against the side of a house with its base 3 feet from the house. Use the Pythagorean Theorem to approxima

scZoUnD [109]

Answer: 12.65 ft

Pythagorean theorem is $a^{2}$ + $b^{2}$ = $c^{2}$