x = 18 1/3
x - 20 + 2x = 35
- 20 + 3x = 35
3x = 35 + 20
3x = 55
x = 55/3
x = 18 1/3
Larry had 3⁄7 of a strawberry-rhubarb pie left over. He split the leftover pie evenly between his 3 children. What fraction of a
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Answer:
The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95
Step-by-step explanation:
Number of red marbles = 12
Number of green marbles = 8
Total number of marbles = 12+8 = 20
Probability of selecting red marble =
Since it is the case of no replacement
Remaining marbles = 20-1 = 19
Number of red marbles = 12-1=11
Number of green marbles = 8
Probability of selecting green marble =
So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag =
Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95