Which of the following expressions shows the distributive property applied to the expression below?

Mathematics

1 answer:

BabaBlast [244]2 years ago

3 0

Answer:

C. (z×6)+(z×35)

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The diagonals of a quadrilateral are of lengths 6cm and 8cm. If the diagonals bisect each other at the right angles. Find the le

maks197457 [2]

Answer:

Each side is 5 cm

Step-by-step explanation:

What you are being told is that the figure is a rhombus. The two sides of a right triangle are 1/2 the size of the diagonals.

a = 3

b = 4

c = the side length of the rhombus.

a^2 + b^2 = c^2

3^2 + 4^2 = c^2

9 + 16 = c^2

25 = c^2

Take the square root of 25

sqrt(c)^2 = sqrt(25)

c = 5

5 0

3 years ago

There are 8 tennis players in a round robin tournament, which means each team will play every other team once. How many matches

Aliun [14]

<h3>Answer: 28</h3>

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Explanation:

Method 1

Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.

There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.

Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.

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Method 2

There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.

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Method 3

Use the nCr combination formula with n = 8 and r = 2

$n C r = \frac{n!}{r!(n-r)!}\\\\8 C 2 = \frac{8!}{2!*(8-2)!}\\\\8 C 2 = \frac{8!}{2!*6!}\\\\8 C 2 = \frac{8*7*6!}{2!*6!}\\\\ 8 C 2 = \frac{8*7}{2!}\\\\ 8 C 2 = \frac{8*7}{2*1}\\\\ 8 C 2 = \frac{56}{2}\\\\ 8 C 2 = 28\\\\$