Answer:
5.553
Step-by-step explanation:
we would subtract 6.75 from 1.197 which in terms would equal 5.553
Answer:
√7x−49√x
Explanation:
First of all, expand by multiplying √7x⋅√x and √7x⋅7√7respectively:
√7x(√x−7√7)=√7x⋅√x−√7x⋅7√7
... you can express √7x as √7⋅√x...
=√7⋅√x⋅√x−√7⋅√x⋅7⋅√7
=√7⋅(√x)2−(√7)2⋅√x⋅7
... the operations squaring and taking the square root "eliminate each other"...
=√7⋅x−7⋅√x⋅7
=√7x−49√x
Hope that this helped!
Substitute the value of b = -2 to the expression

the answer is in the picture above
Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then

,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since

, f(6) = 5
Answer: 5