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2 years ago

21. You are baking cookies. You have 7 cups of flour. You use 2 cups of

Mathematics

1 answer:

KIM [24]2 years ago

6 0

7 cups - 2 cups = 5 cups of flour

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8-5x =2x + 20 <br> Simplify<br> I’ll give brainliest

kobusy [5.1K]

Answer:

X= - 12/7 i hope it is helpful have a nice day if you want steps i will show you

6 0

2 years ago

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The area of a rectangle is 20 square inches. If the length is 4 inches less than 6 times the width, then find the dimensions of

Tpy6a [65]

Step-by-step explanation:

Let the width=x

Length =6x-4

As we know that in a rectangle

${\boxed{\sf Area=LB}}$

Substitute the values

$\hookrightarrow\sf x (6x-4)=20$

$\hookrightarrow\sf 6x^2-4x=20$

$\hookrightarrow\sf 6x^2-4x-20=0$

Here a=6, b=-4, c=-20.
use quadratic formula

$\hookrightarrow\sf x=\dfrac {1}{3}+\dfrac {1}{3}\sqrt {31} \quad or \quad \dfrac {1}{3}+\dfrac {-1}{3}\sqrt {31}$

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2 years ago

Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)

fredd [130]

Answer:

$f(x)=\frac9{x+1}\\ f'(x)=-\frac9{(x+1)^2}\\ f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\\ |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\\ x_1=2\ \vee\ x_2=-4\\ f(x_1)=f(2)=\frac9{2+1}=3\\ f(x_2)=f(-4)=\frac9{-4+1}=-3$

First tangent line:

$y=f'(x_1)\cdot (x-x_1)+f(x_1)\ \to \ y=-1(x-2)+3\ \to \ y=-x+5$

Second tangent line:

$y=f'(x_2)\cdot (x-x_2)+f(x_2)\ \to \ y=-1(x+4)-3\ \to \ y=-x-7$

Notice: slope of -1 means that both $f'(x_1), \ f'(x_2)$ are equal to -1, so $f'(x_1)=-1 \ and \ f'(x_2)=-1$

6 0

2 years ago

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Two less than six times a number is the same as thirteen more than a number. Find the number.

NNADVOKAT [17]

6x - 2 = x + 13
Subtract x
5x - 2 = 13
Add 2
5x = 15, x = 3
Solution: the number is 3

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2 years ago

What does 3n-10=b+4???

Rufina [12.5K]

You cant solve but u can simplify which would be 2b=14

4 0

2 years ago