Answer:
The speed V = 194.03 mph
Direction = 3.6° northeast
Step-by-step explanation:
The distance of the trip = 291 miles
The direction of flight = 9.1 degrees northeast
Speed of the prevailing wind = 25 mph
Direction of wing = southeast = 45 degrees South of East
The speed heading to Ivy Cliffs = V₁
V×(sin(9.1) + cos(9.1)) + 25×(-sin(45) + cos(45)) × t₁ = 291 miles
V×(sin(9.1) + cos(9.1)) + 25×(sin(45) + -cos(45)) × t₂ = 291 miles
t₁ + t₂ = 3 hours
(V×(sin(9.1)-25×(sin(45))j + (V×cos(9.1) + 25×cos(45))i
The magnitude V² = V²+29.32·V +625= 291²/t₁²......(1)
Also on the return trip we have;
V²-29.32·V +625= 291²/(3-t₁)²..........................................(2)
Subtracting equation (2) from (1) gives;
58.64·V = 291²/t₁² - 291²/(3-t₁)² = 291²×(6·t-9)/(t²·(t-3)²)
V = 291²×(6·t-9)/(t²·(t-3)²)/58.64
Substituting the value of V in (2) with a graphing calculator gives;
t₁= 1.612 or 1.387
Given that magnitude of the speed going > return = V² for t₁ < t₂
t₁ = 1.387, t₂ = 1.612
From V²+29.32·V +625= 291²/t₁², we have
V²+29.32·V +625= 291²/1.387²
Which gives
V²+29.32·V -43336.5 = 0
(V + 233.35)(V-194.03) = 0
V = -233.35 mph or V = 194.03 mph
Given that V is a natural number, we have, V = 194.03 mph.
The direction is given by the relation;
V×(sin(9.1) + cos(9.1)) + 25×(-sin(45) + cos(45)) × t₁ = 291 miles
V×(sin(9.1) + cos(9.1)) + 25×(-sin(45) + cos(45)) × t₁ = 291 miles
194.03×sin(9.1 degrees)-25×sin(45 degrees)j + 194.03×cos(9.1 degrees) + 25×cos(45 degrees)i = 291/1.387
13j + 209.27i = 208.81 mph
The angle tan θ = 13/209 = 0.00622
θ = tan⁻¹(13/209.27) = 3.6°.
