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True [87]
3 years ago
10

Lucinda wants to build a square sandbox but has no way of measuring angles. Explain how she can make sure that the samdbox is me

ansuring only length..
A) Arrange four equal-length sides so the diagonals bisect each other.

B) Arrange four-length sides so the diagonalsare equal in length

C) Make each diagonal the same length as four-length sides

D) This is not possible, Luninda has to be able to measure a right angle.
Mathematics
1 answer:
amm18123 years ago
8 0
<span>Option B. Arrange four-length sides so the diagonals are equal in length. Since a square is a rectangle with four equal sides the diagonals should bisect each other at each length and at 90 degrees to each other. This is really important. If the diagonals are equal in length and bisect each other at equal distance then the sandbox is measuring length and has equal angles which is a square by definition</span>
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Solve the two-step equation. − 2 3 x – 21 4 = 27 4
svetoff [14.1K]

Answer:

Step-by-step explanation:

I'm going to assume that the problem is -23x -214 = 274

And in that case...

1. First isolate the x-value by adding 214 to both sides of the equation:

-23x = 488

2. Then, divide both sides by -23 to truly get x alone:

x = -\frac{488}{23} or -21.22

7 0
3 years ago
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Kevin made a jewelry box with the dimensions shown width: 15 cm length: 10 cm depth: 5 cm. what is the volume of the jewelry box
ziro4ka [17]

you need to know the mass of the jewelry box before you can know the volume but i can help you multiply th 15 and the 10 to get the mass most likely then divided what you have from 15 x 10 by the depth and you have your answer just be sure to round it off!


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3 years ago
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Given logx 2=p and logx 7=q , express log7 4x² in terms of p and q​
kodGreya [7K]

Answer:

[2(p + 1)]/q

Step-by-step explanation:

logx 2 = p

logx 7 = q

log7 4x² = log7 (2x)²

= (logx (2x)²)/(logx 7)

= (2 logx 2x)/(logx 7)

= (2 logx 2 + 2 logx x)/(logx 7)

= (2p + 2)/q

= [2(p + 1)]/q

5 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
If c = 4 and d = 5, find c:d.<br><br> 1:5<br> 4:5<br> 5:4
nadya68 [22]
The answer would be the second choice. 4:5
5 0
3 years ago
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