I believe it is either B or C. I am leaning towards C
1 g/cm³ --------------- 0.1 kg/dL
7.86 g/cm³ ---------- ?
7.86 x 0.1 / 1 => 0.786 kg/dL
D = m / V
0.786 = 3.56 / V
V = 3.56 / 0.786
V = 4.529 dL
<span>hope this helps!</span>
1.) Air can be separated into its constituents such as oxygen, nitrogen etc.
2.) Air has a variable composition because at different places different amount of gases are present in air.
Answer:
n C2H5OH = 0.2496 mol
Explanation:
- moles (n) = mass / molecular weight
∴ m C2H5OH = 11.5 g
∴ Mw C2H5OH = (2)(12.011) + (6)(1.00794) + 15.9994 = 46.069 g/mol
⇒ n C2H5OH = (11.5 g)/(46.069 g/mol) = 0.2496 mol C2H5OH
