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krok68 [10]
3 years ago
7

6. How many moles are represented by 11.5 g of C2H5OH?

Chemistry
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

n C2H5OH = 0.2496 mol

Explanation:

  • moles (n) = mass / molecular weight

∴ m C2H5OH = 11.5 g

∴ Mw C2H5OH = (2)(12.011) + (6)(1.00794) +  15.9994 = 46.069 g/mol

⇒ n C2H5OH = (11.5 g)/(46.069 g/mol) = 0.2496 mol C2H5OH

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Calculate the moles of calcium oxalate formed from 5 grams of potassium oxalate (molar mass 184.24 g/mol) the mole mole ratio fr
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5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).

We can calculate the moles of CaC₂O₄ obtained considering the following relationships.

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5 g K_2C_2O_4 \times \frac{1molK_2C_2O_4}{184.24gK_2C_2O_4}  \times \frac{1molCaC_2O_4}{2molK_2C_2O_4} = 0.03molCaC_2O_4

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.

Learn more: brainly.com/question/15288923

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