The ratio of effusion rates for the lightest gas H₂ to the heaviest known gas UF₆ is 13.21 to 1
<h3>What is effusion?</h3>
Effusion is a process by which a gas escapes from its container through a tiny hole into evacuated space.
Rate of effusion ∝ 1/√Ц, (where Ц is molar mass)
Rate H₂ = 1/√ЦH₂
Rate UF₆ = 1/√ЦUF₆
Therefore, Rate H₂/ Rate UF₆ = √ЦH₂/√ЦUF₆
ЦH₂= 2.016 g/mol
ЦUF₆= 352.04 g/mol
Rate H₂ / Rate UF₆ = √352.04/√2.016 = 18.76/1.42
Rate H₂ / Rate UF₆ = 13.21
Therefore, H₂ is lower mass than UF₆. Thus H₂ gas will effuse 13 times more faster than UF₆ because the most probable speed of H₂ molecule is higher; therefore, more molecules escapes per unit time.
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The data indicates a direct relationship with a positive slope.
<h3>What is direct relationship?</h3>
Direct relationship is a type of relation in which if one factor increases the other will also increases and vice versa. This data represents direct relationship because the increase occur in one value causes increase of another value so we can conclude that the data indicates a direct relationship with a positive slope.
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Answer:
The process of dissolving increases entropy because the solute particles become separated from one another when a solution is formed.
Answer:
The number of moles of nitrogen in the tank are 1,98.
Explanation:
We apply the ideal gas law, convert the temperature unit in Celsius to degrees Kelvin, solve for n (number of moles). The gas constant R is used with a value of 0.082 l atm / K mol:
0°C= 273 K ---> 19, 71°C= 273 + 19,71= 292, 71K
PV= nRT ---> n=PV/RT
n= 4,97 atm x 9,583 L/ 0.082 l atm / K mol x 292, 71K=<em> 1, 98 mol</em>
