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3 years ago

Please help-

Chemistry

1 answer:

Oksanka [162]3 years ago

4 0

Answer:

you are not posted question

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Solutions _________________________________________. a. are always composed of a solid dissolved in a liquid b. can be composed

rjkz [21]

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3 years ago

How many liters of

Kruka [31]

The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂

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4 years ago

Seven carbon chain with CH3 attached to second and third carbon

Nikitich [7]

Answer:

2,3-dimethylheptane.

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

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CH₃ CH₃

Explanation:

Hello there!

In this case, according to the given instructions, it is possible to draw the organic chemical structure by connecting seven carbon atoms along the parent chain with two methyl substituents at the second and third carbon atoms; thus, the resulting structure is:

CH₃ - CH - CH-CH₂-CH₂-CH₂-CH₂

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CH₃ CH₃

Furthermore, the name would be 2,3-dimethylheptane according to the IUPAC rules for nomenclature.

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3 years ago

Calculate the mass percent composition of sulfur in Al2(SO4)3. Calculate the mass percent composition of sulfur in Al2(SO4)3. 28

ludmilkaskok [199]

Answer:

The mass percent of sulfur is 28.12% (option 1)

Explanation:

Step 1: Data given

Atomic mass of Al = 26.98 g/mol

Atomic mass of S = 32.065 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate the molar mass of Al2(SO4)3

In 1 molecule Al2(SO4)3 we have 2 Aluminium atom, 3 Sulfur atoms and 12 oxygen atoms

Molar mass of Al2(SO4)3 = 2*26.98 + 3*32.065 + 12*16 .0

Molar mass of Al2(SO4)3 = 342.155 g/mol

Step 3: Calculate the mass percent of sulfur

In 1 molecule Al2(SO4)3 we have 2 Aluminium atom, 3 Sulfur atoms and 12 oxygen atoms

Mass % sulfur = (3*atomic mass of S/ molar mass of Al2(SO4)3) * 100 %

Mass % sulfur = (3*32.065 / 342.155) * 100%

Mass % sulfur = 28.12 %

The mass percent of sulfur is 28.12% (option 1)

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4 years ago