Answer:
A. it is the lowest at low temperatures
Explanation:
At low temperature the kinetic energy of a molecule is low. The kinetic energy is directly proportional to the temperature of the molecule. The kinetic energy of a molecule increases with the increase in the temperature that energize the molecules of a substance and makes them to move faster than before.
As the kinetic energy is proportional to temperature so it does not increase with decrease in the temperature (low temperature). The kinetic energy varies with the change in the temperature and it is not same at all temperature. The kinetic energy is highest at high temperature. Thus, option A is correct.
Answer:
The temperature change was 10.04 °C.
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, there is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:
Q = c * m * ΔT
Where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case you know:
- c= 1
Replacing:
7,529 cal= 1 *750 g* ΔT
Solving you get:
ΔT=
ΔT= 10.04 °C
So, <u><em>the temperature change was 10.04 °C.</em></u>
Explanation:
A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by
E=hf=hcλ(energy of a photon)E=hf=hcλ(energy of a photon),
where E is the energy of a single photon and c is the speed of light. When working with small systems, energy in eV is often useful. Note that Planck’s constant in these units is h = 4.14 × 10−15 eV · s.
Since many wavelengths are stated in nanometers (nm), it is also useful to know that hc = 1240 eV · nm.
These will make many calculations a little easier.
All EM radiation is composed of photons. Figure 1 shows various divisions of the EM spectrum plotted against wavelength, frequency, and photon energy. Previously in this book, photon characteristics were alluded to in the discussion of some of the characteristics of UV, x rays, and γ rays, the first of which start with frequencies just above violet in the visible spectrum. It was noted that these types of EM radiation have characteristics much different than visible light. We can now see that such properties arise because photon energy is larger at high frequencies.
Answer:
<h2>
The bombing of Hiroshima ended World War II.</h2>
Explanation:
[The scientific method includes these steps:
Observation
Hypothesis
Experimentation
Data Analysis
Conclusion]
The first two Hypothesis can be tested with the scientific method, you cannot go back in time and observe or experiment with the bombing of Hiroshima to deduce whether or not it ended World War II.
