Answer:
= -4.2°C
= 49.4°C
Explanation:
A Carnot cycle is known as an ideal cycle in thermodynamic. Therefore, in theory, we have:
|
| = 
Similarly,
|
| = |
| + |
|
During winter, the value of || = 20°C = 273.15 + 20 = 293.15 K and || = 1.5 kW. Therefore,
|| = 0.75( - )
Similarly,
|
| = 1 -
1.5/0.75*(293.15-) = 1 - (/293.15
Further simplification,
= -4.2°C
During summer, = 25°C = 273.15+25 = 298.15 K, and || = 1.5 kW. Therefore,
|| = 0.75( - )
Similarly,
|
| = 
- 1
1.5/0.75*( - 298.15) = (/298.15
Further simplification,
= 49.4°C
Answer:
6
Explanation:
The maximum number of electrons in the orbitals of sub-levels are given as:
for s-sublevel we have two electrons and one orbital
p-sublevel we have six electrons and three orbitals
d-sublevel we have ten electrons and five orbitals
f- sublevel we have fourteen electrons and seven orbitals
The second energy level is represented by the p-sub-level and it will accommodate 6 electrons.
Answer:
a) 0.525 mol
b) 0.525 mol
c) 0.236 mol
Explanation:
The combustion reactions (partial and total) will be:
C₇H₁₆ + (15/2)O₂ → 7CO + 8H₂O
C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O
---------------------------------------------------
2C₇H₁₆ + (37/2)O₂ → 7CO + 7CO₂ + 16H₂O
It means that the reaction will form 50% of each gas.
a) 0.525 mol of CO
b) 0.525 mol of CO₂
c) The molar mass of heptane is: 7*12 g/mol of C + 16*1 g/mol of H = 100 g/mol
So, the number of moles is the mass divided by the molar mass:
n = 11.5/100 = 0.115 mol
For the stoichiometry:
2 mol of C₇H₁₆ -------------- (37/2) mol of O₂
0.115 mol of C₇H₁₆ --------- x
By a simple direct three rule:
2x = 2.1275
x = 1.064 mol of O₂
Which is the moles of oxygen that reacts, so are leftover:
1.3 - 1.064 = 0.236 mol of O₂
Answer:
Nothing.
Step-by-step explanation:
Both Al(OH)₃ and CaSO₄ are insoluble in water, so their ions cannot come into contact and react.
