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kap26 [50]
3 years ago
5

A package of aluminum foil is 63.2 yd long, 11 in. wide, and 0.00035 in. thick. If aluminum has a density of 2.70 g/cm³, what is

the mass, in grams, of the foil?
Chemistry
1 answer:
mina [271]3 years ago
3 0

Answer:

Mass of aluminium foil = 387.57_g

Explanation:

density of aluminium foil 2.70 g/cm³,

1_yd = 91.44_cm

1_in = 2.54_cm

Length of aluminum foil = 63.2_yd = 5779.008_cm

Width of aluminium foil = 11 in = 27.94_cm

Thickness of aluminium foil = 0.00035_in. = 0.000889_cm

Volume of aluminium foil = length × width × thickness = 5779.008_cm × 27.94_cm × 0.000889_cm = 143.54_cm^3

Mass of aluminium foil = (volume of aluminium foil) × (density of aluminium foil) = 143.54_cm³ × 2.70 g/cm³ = 387.57_g

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It is known that the kinetics of recrystallization for some alloy obey the Avrami equation andthat the value of n in the exponen
Paul [167]

Answer:

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

Explanation:

For Avrami equation:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ k = \dfrac{-In(1-y)}{t^n}

To calculate the value of k which is a dependent variable for the above equation ; we have:

k = \dfrac{-In(1-0.40)}{200^{2.5}}

k = 9.030 \times 10 ^{-7}

The time needed for 50% transformation can be determined as follows:

y = 1-e ^{(-kt^n)} \\ \\ e^{(-kt^n)} = 1-y\\ \\ -kt^n = In(1-y) \\ \\ t =[ \dfrac{-In(1-y)}{k}]^{^{1/n}}

t_{0.5} =[ \dfrac{-In(1-0.4)}{9.030 \times 10^{-7}}]^{^{1/2.5}}

= 200.00183 min

The rate of reaction for Avrami equation is:

rate = \dfrac{1}{t_{0.5}}

rate = \dfrac{1}{200.00183}

rate = 0.00499 / min

rate of recrystallization = 4.99 × 10⁻³ min⁻¹

8 0
3 years ago
The reaction between sodium and oxygen ( balanced with words)
irina1246 [14]
There will be chemical reaction(equation4Na+02--2Na20
3 0
4 years ago
C
Schach [20]

Answer:

2.74 M

Explanation:

Given data:

Mass of sodium chloride = 80.0 g

Volume of water = 500.0 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the mL into L.

500.0 mL× 1 L /1000 mL =  0.5 L

In next step we will calculate the number of moles of sodium chloride.

Number of moles = mass/molar mass

Number of moles = 80.0 g/ 58.4 g/mol

Number of moles = 1.37 mol

Molarity:

M =  1.37 mol/ 0.5 L

M =  2.74 M

8 0
3 years ago
What's a hypothesis for Which fruit contains the most vitamin c?
yan [13]
Find a fruit you think is the one that contains the most vitamin C.

For example: kiwi

Answer: I hypothesize that kiwi contains the most vitamin C

Then after that you test your hypothesis by comparing fruit that contains vitamin C in an experiment.
4 0
3 years ago
The specific heat of silver is 0.234 j/(g·c). calculate the amount of energy that is needed to raise the temperature of 175 g of
Elodia [21]
Heat energy is supplied to materials and can cause an increase in temperature of the material. the formula is as follows
H = mcΔt
where H - heat energy 
m - mass of material 
c - specific heat 
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substituting the values 
H = 175 g x 0.234 Jg⁻¹°C⁻¹ x 17.5 °C
H = 716.6 J 
716.6 J is required 
3 0
3 years ago
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