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kap26 [50]
2 years ago
5

A package of aluminum foil is 63.2 yd long, 11 in. wide, and 0.00035 in. thick. If aluminum has a density of 2.70 g/cm³, what is

the mass, in grams, of the foil?
Chemistry
1 answer:
mina [271]2 years ago
3 0

Answer:

Mass of aluminium foil = 387.57_g

Explanation:

density of aluminium foil 2.70 g/cm³,

1_yd = 91.44_cm

1_in = 2.54_cm

Length of aluminum foil = 63.2_yd = 5779.008_cm

Width of aluminium foil = 11 in = 27.94_cm

Thickness of aluminium foil = 0.00035_in. = 0.000889_cm

Volume of aluminium foil = length × width × thickness = 5779.008_cm × 27.94_cm × 0.000889_cm = 143.54_cm^3

Mass of aluminium foil = (volume of aluminium foil) × (density of aluminium foil) = 143.54_cm³ × 2.70 g/cm³ = 387.57_g

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If a solution containing
tankabanditka [31]

Answer:

Hg(NO₃)₂(aq) + Na₂SO₄(aq)   →   2NaNO₃(aq) + HgSO₄(s)

Moles of Hg(NO₃)₂ = 55.42 / 324.7 ==> 0.1707 moles

Moles of Na₂SO₄ = 16.642 / 142.04 ==> 0.1172 moles

Limiting reagent is Na₂SO₄ as it controls product formation

Moles of HgSO₄ formed = 0.1172 moles

                                        = 0.1172 x 296.65

                                        = 34.757g

Explanation:

6 0
3 years ago
What are the two components of a solution? Write two properties of a solution
BARSIC [14]
The two components of a solution are solvent and solute.

A solution is a homogenous mixture, stable, and the particles are very small.


3 0
2 years ago
A geology student found an irregularly shaped rock, with a mass of 28.63 grams, and placed it into a graduated cylinder with a v
EastWind [94]

Density is simply the ratio of mass over volume. In this case, the volume of the rock is the difference of after and before it was dropped into the cylinder.

volume = 19.73 mL – 13.31 mL = 6.42 mL

 

density = 28.63 g / 6.42 mL

<span>density = 4.46 g/mL</span>

5 0
3 years ago
Read 2 more answers
What is the charge of the nucleus ? Why ?
mars1129 [50]

Answer:

A nucleus is a positive charge

Explanation:

A nucleus is made up of protons and neutrons. Protons have a positive charge and neutrons have a neutral charge.

8 0
2 years ago
Calculate the number of photons having a wavelength of 12.0 μm required to produce 1.0 kJ of energy.
nika2105 [10]

Answer:

N = 603.32 × 10 ²⁰

Explanation:

Given data:

Wavelength of photon = 12.0 μm or 12 × 10 ⁻⁶ m

Energy = 1.0 KJ  or 1000 j

Number of photons = ?

Solution:

Formula:

E  = n . h . f

E = energy

N = number of photons

h = planck's constant

f = frequency

it is known that

f = c/λ

thus,

E = N . h . c / λ

Now we will put the values in formula.

1000 j = ( N. 6.63 × 10 ⁻³⁴ j.s × 3 × 10⁸ m/s ) / 12 × 10 ⁻⁶ m

N = 1000 j ×12 × 10 ⁻⁶ m  / 6.63 × 10 ⁻³⁴ j.s × 3 × 10⁸ m/s

N = 12000 j × 10 ⁻⁶ m / 19.89 × 10 ⁻²⁶ j. m

N = 603.32 × 10 ²⁰

4 0
2 years ago
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