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wel
4 years ago
7

Suppose that a person eats a diet of 2391 Calories per day.a.) Convert this energy into J. Express your answer using four signif

icant figures.b.) Convert this energy into kJ. Express your answer using four significant figures.c.) Convert this energy into kWh. Express your answer using four significant figures.
Chemistry
1 answer:
alekssr [168]4 years ago
8 0

Explanation:

(a)

The given data is:-

Energy = 2391 Calories

The conversion of calories to J is shown below as:-

1 calorie = 4.184 J

So,

Energy = 4.184 * 2391 J = 10003.944 J

Answer in four significant digits: - 1.000\times 10^4\ J

(b)

The conversion of calories to kJ is shown below as:-

1 calorie = 0.004184 kJ

So,

Energy = 0.004184 * 2391 kJ = 10.003944 kJ

Answer in four significant digits: - 1.000\times 10\ kJ

(c)

The conversion of calories to kWh is shown below as:-

1 calorie = 1.1622\times 10^{-6} kWh

So,

Energy = 1.1622\times 10^{-6}\times 2391 kWh = 0.002778873 kWh

Answer in four significant digits: - 0.002779\ kWh

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<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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