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2 years ago

7

A plane traveling with a velocity measured in meters per second, is described by vector = 〈6,5〉. Find the speed of the plane. √3

0 √61 30 61

2 answers:

masha68 [24]2 years ago

6 0

Answer:

√61

Step-by-step explanation:

The speed is the magnitude of the velocity.

= sqrt (6^2 + 5^2) = √61

Mrac [35]2 years ago

6 0

Answer:

Answer:

√61

Step-by-step explanation:

The speed is the magnitude of the velocity.

= sqrt (6^2 + 5^2) = √61

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Hardy has three times as many tennis balls as kerns. They have 940 tennis balls in all. How many tennis balls does Hardy have th

topjm [15]

Answer:

Hardy has 470 more tennis balls than Kerns.

Step-by-step explanation:

Given that:

Total number of tennis balls = 940

Let,

x represents the number of tennis balls Hardy has.

y represents the number of tennis balls Kerns has.

According to given statement,

x+y=940 Eqn 1

x = 3y Eqn 2

Putting x = 3y in Eqn 1

3y+y=940

4y=940

Dividing both sides by 4

$\frac{4y}{4}=\frac{940}{4}\\y=235$

Putting y=235 in Eqn 2

x = 3(235)

x = 705

Difference = Hardy's tennis balls - Kerns' tennis balls

Difference = 705 - 235 = 470

Hence,

Hardy has 470 more tennis balls than Kerns.

3 0

2 years ago

When are the absolute value and the opposite of a rational number equal

natulia [17]

|a| = -a if a < 0

The absolute value and the opposite of rational number is equal when a number is negative.

Examples:

|-7| = - (-7) = 7

|-0.5| = - (-0.5) = 0.5

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3 years ago

Expand and simplify pla

k0ka [10]

Y = f(3f - 4g + 3) +7g(3f - 4g + 3)
= 3f^2 - 4fg + 3f + 21fg - 28g^2 + 21g
= 3f^2 + 3f + 17fg + 21g - 28g^2

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2 years ago

There are 7 days in 1 week. How many days are there<br> in 4 weeks?

otez555 [7]

Answer:

28 days

Step-by-step explanation:

You multiply 7 by 4 for find the number of days in 4 weeks, since 1 week is 7 days: 7 × 4 = 28.

Hope this helps!

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2 years ago

Read 2 more answers

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago