Given:
M=(x1, y1)=(-2,-1),
N=(x2, y2)=(3,1),
M'=(x3, y3)= (0,2),
N'=(x4, y4)=(5, 4).
We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.
For a parallelogram, opposite sides are equal
If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.
To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,
Slope of MN= Slope of M'N'.
Slope of MM'=NN'.

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.
Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.
Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.
Answer:
It is D or B. If i am not mistaken
Answer:
Step-by-step explanation:
Depends on what you mean by multiplying by - 1. I assume you are not going to multiply the y or f(x) term by - 1.
If that is so, take an example. Suppose you have a graph that is y=x^2
That's a parabola that opens upwards and it has a line going through its focus which is a point on the +y axis.
When you multiply the right hand side by - 1, the graph you get will be y = - x^2.
That opens downward and the focus is on the - y axis.
That means that the effect of the graph is that it flips over the x axis, which I think is the third answer.
Answer:
b = -1.4
Step-by-step explanation: