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melamori03 [73]

2 years ago

6

Nate and his friends are building a skateboard ramp for an upcoming contest. The length of the ramp on the blueprint is 7.6 inch

es. If the scale on the blueprint is 1 inch to 4 feet, what is the actual length of the ramp?

1 answer:

ICE Princess25 [194]2 years ago

7 0

Answer:

30.4 feet.

Step-by-step explanation:

We have been given the length of the ramp on the blueprint is 7.6 inches. The scale on the blueprint is 1 inch to 4 feet. We are asked to find the actual length of the ramp.

We will use proportions to solve our given problem as:

$\frac{\text{Actual length}}{\text{Scale length}}=\frac{4\text{ ft}}{1\text{ inch}}$

Now, we will substitute the scale length of ramp in our proportion as:

$\frac{\text{Actual length}}{7.6 \text{ Inches}}=\frac{4\text{ ft}}{1\text{ inch}}$

$\frac{\text{Actual length}}{7.6 \text{ Inches}}\cdot 7.6 \text{ Inches}=\frac{4\text{ ft}}{1\text{ inch}}\cdot 7.6 \text{ Inches}$

$\text{Actual length}=4\text{ ft}\cdot 7.6$

$\text{Actual length}=30.4\text{ ft}$

Therefore, the actual length of the ramp would be 30.4 feet.

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Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

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Option (A) is false

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Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

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$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

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$d_{AB}\:=\sqrt{37}$

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Given the vertices of the segment JK

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From the graph, it is clear that the length of JK = 5 units

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Given the vertices of the segment GH

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$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

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Thus,

$d_{AB}\ne d_{JK}$

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$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

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