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Artist 52 [7]
4 years ago
14

A baseball flying through the air has_?​

Chemistry
2 answers:
Andrew [12]4 years ago
8 0

Answer:

kinetic energy

Explanation:

A baseball flying through the air has kinetic energy because of its motion

hram777 [196]4 years ago
3 0
The answer is kinetic energy
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A sample of gas has temperature of 372 K and pressure of 3.8 ATM. If the temperature is increased to 550 K, what is the new pres
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Answer: The correct answer is 5.6atm.

Explanation: Since we only have information on the pressure and temperature, we will use Gay-Lussac's Law: \frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }. Now that we have the formula, let's plug in our given information!

\frac{3.8atm}{372K} =\frac{P_{2} }{550K}

We must find the value P_{2}. To do this, we will write a stoichiometric equation to solve this.

P_{2} =\frac{3.8atm*550K}{372K}

Let's input the numbers into a scientific calculator to get our answer!

P_{2} =\frac{3.8atm*550K}{372K}=5.6 atm

Given all of this work, the value P_{2} equals 5.6 atm.

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2 years ago
PLS HELP THIS IS ACTUALLY SCIENCE BUT PLS HELP<br> What is the greenhouse effect?
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Answer:

the greenhouse effect is a natural process that warms the Earth's surface. When the Sun's energy reaches the Earth's atmosphere, some of it is reflected back to space and the rest is absorbed and re-radiated by greenhouse gases. ... The absorbed energy warms the atmosphere and the surface of the Earth.

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3 years ago
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When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
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Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

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E_n=-13.6\times \frac{Z^2}{n^2}ev

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Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

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