Answer:
0.2402 M
Explanation:
0.945 L sol contains = 0.227 moles
1 L sol will contain = (0.227/0.945)*1 = 0.2402 moles
Molarity = 0.2402 moles/L or M
Answer:
Mass of sample in mg = 15,285 mg
Explanation:
Given:
Volume of urine sample = 15 ml
Density of sample = 1.019 g/ml
FInd:
Mass of sample in mg
Computation:
Mass = density x volume
Mass of sample in mg = Volume of urine sample x Density of sample
Mass of sample in mg = 1.019 x 15
Mass of sample in mg = 15.285 gram
Mass of sample in mg = 15.285 x 1,000
Mass of sample in mg = 15,285 mg
Nobles gases, since they all have 8 e- on their last layer of electrons.
Answer:
It has to have a problem base and a realistic explanation.
Explanation:
It needs to have enough information for you to be able to come up with an answer and realistic explanation.
Hope I helped :)
