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lions [1.4K]
3 years ago
15

7. What are the coefficients when the equation below is balanced?

Chemistry
2 answers:
gogolik [260]3 years ago
8 0

Answer:

A

Explanation:

ivann1987 [24]3 years ago
4 0

Answer:

A

Explanation:

In order to balance an equation,the number of atoms of elements on the right side must equal the number of atoms of the same elements on the left side.After balancing the equation,C has 1 atom on both the left and right side,H has 4 atoms each on both sides of the equation and O has 4 atoms each on both sides of the equation,hence balanced.

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How many molecules are in 7.34 g of Na2CO3
kenny6666 [7]

Answer:

The answer is 105.98844.

<h3>Explanation: </h3>

We assume you are converting between grams Na2CO3 and mole. You can view more details on each measurement unit: molecular weight of Na2CO3 or mol This compound is also known as Sodium Carbonate.

7 0
3 years ago
If an object has a density of 0.00018 g/cm cubed, what density would it be if it had a mass of 10kg
Vladimir79 [104]

Answer:

Explanation:

first to get the density of some thing you have to devide the mass by the volume so 0.00018 (divided) by 10 kg and that gives you ur answer

3 0
2 years ago
PLEASEEEEEEEEEEEE HELPPPPPPPP I BEGGGGG FOR HELPPPPP
Elza [17]

Answer: There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles

1 mole of H_2O contains =  6.023\times 10^{23} molecules

Thus 3.5 moles of H_2O contains =  \frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23} molecules.

There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

3 0
3 years ago
Radioactive radium has a half-life of approximately 1,599 years. The initial quantity is 13 grams. How much (in grams) remains a
Luda [366]

The quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

<h3>What is half life period? </h3>

The time taken by substance to reduce to its half of its initial concentration is called half life period.

We will use the half- life equation N(t)

N e^{(-0.693t) /t½}

Where,

N is the initial sample

t½ is the half life time period of the substance

t2 is the time in years.

N(t) is the reminder quantity after t years .

Given

N = 13g

t = 350 years

t½ = 1599 years

By substituting all the value, we get

N(t) = 13e^(0.693 × 50) / (1599)

= 13e^(- 0.368386)

= 13 × 0.691

= 8.98

Thus, we calculated that the quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

learn more about half life period:

brainly.com/question/20309144

#SPJ4

4 0
1 year ago
I need help on this.
masya89 [10]

i love math but sadly i am dumb

3 0
3 years ago
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