Question

g In the elimination reaction of t-butanol and t-butyl bromide. A. They have a common intermediate and require a strong base B. Both reactions share a common intermediate and involve a similar leaving group C. One reaction goes through an E1 mechanism and the other an E2 mechanism D. Both reactions share a common intermediate and differ only in the leaving group

Answer 1

Answer:

Both reactions share a common intermediate and differ only in the leaving group

Explanation:

The elimination reaction of tertiary alkyl halides usually occur by E1 mechanism. In E1 mechanism, the substrate undergoes ionization leading to the loss of a leaving group and formation of a carbocation.

Loss of a proton from the carbocation completes the reaction mechanism yielding the desired alkene.

In the cases of t-butanol and t-butyl bromide, the mechanism is the same. The both reactions proceed by E1 mechanism. The leaving groups in each case are water and chloride ion respectively.