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Mathematics

1 answer:

san4es73 [151]1 year ago

7 0

The values from the given replacement set make up the solution set of the inequality is {8, 9, 10]

<h3>How to solve inequality?</h3>

In mathematics, an inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions.

Let's solve the inequality to find the replacement set that make up the solution set of the inequality as follows:

m + 7 < 18

subtract 7 from both sides of the inequality

m + 7 < 18

m + 7 - 7 < 18 - 7

m < 11

Therefore, the set of value of m is less that 11.

The solution sets are {8, 9, 10}

learn more on inequality here:brainly.com/question/8035078

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Can someone please helppp will give you lots of points and brainliest

harkovskaia [24]

4. SOLVE FOR X:

Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.

67 = 12x - 5

67 + 5 = 12x - 5 + 5

72/12 = 12x/12

6 = x

x = 6

SOLVE FOR Y:

Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.

y = 67 degrees.

5. SOLVE FOR Y:

Alternate exterior angles: 6(x - 12) = 120

6x - 72 + 72 = 120 + 72

6x/6 = 192/6

x = 32

SOLVE FOR Y:

6((32) - 12) + y = 180

192 - 72 + y = 180

120 + y - 120 = 180 - 120

y = 60

8 0

3 years ago

Read 2 more answers

Which expression is equivalent to sqrt2/^3sqrt2

zimovet [89]

The given expression is $\frac{\sqrt{2}}{\sqrt[3]{2}}$

This can be simplified using the radical properties as below

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\$

Now using exponent properties we can write

$\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\$