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liubo4ka [24]
4 years ago
14

1. A = s · s = 7 · 7 = 49; 49 square inches

Mathematics
1 answer:
IrinaVladis [17]4 years ago
4 0
I don't get what you are trying to ask here. can you tell me what you are talking about?
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50 POINTS + BRAINLIEST <br><br> PLEASE DONT STEAL POINTS
Nina [5.8K]

Answer:

1/2 of

4/3 x

3 x

1 unit of

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
John can cut 3 yards of grass per day if he works seven days how many yards can he cut in a week
Solnce55 [7]

Answer:

21

Step-by-step explanation:

Since there are 7 days in a week, we'll multiply 3 by 7, resulting in an answer of: 21.

7 0
3 years ago
Verify which of the following are identities.
IrinaVladis [17]

Answer:

d. only the first equation is an identity

Step-by-step explanation:

4 0
3 years ago
A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial,
Tresset [83]

Answer:

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

Step-by-step explanation:

Given - A lab animal may eat any one of three foods each day. Laboratory records show that if the animal chooses one food on one trial, it will choose the same food on the next trial with a probability of 50%, and it will choose the other foods on the next trial with equal probabilities of 25%.

To find - If the animal chooses food #1 on an initial trial, what is the probability that it will choose food #2 on the second trial after the initial trial?

Proof -

By the given information, we get the stohastic matrix

H = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]

As we know that,

The matrix is a Markov chain x_{k+1} = Hx_{k}

Let

The initial state vector be

x_{0} = \left[\begin{array}{ccc}1\\0\\0\end{array}\right]

we choose this initial vector because given that If the animal chooses food #1 on an initial trial.

Now,

x_{1} = Hx_{0} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}1\\0\\0\end{array}\right] \\= \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]

∴ we get

x_{1} = \left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right]

Now,

x_{2} = Hx_{1} \\ = \left[\begin{array}{ccc}0.5&0.25&0.25\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]\left[\begin{array}{ccc}0.5\\0.25\\0.25\end{array}\right] \\= \left[\begin{array}{ccc}0.25+0.0625+0.0625\\0.125+0.125+0.0625\\0.125+0.0625+0.125\end{array}\right]\\= \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]

∴ we get

x_{2} = \left[\begin{array}{ccc}0.375\\0.3125\\0.3125\end{array}\right]

∴ we get

The probability that it will choose food #2 on the second trial after the initial trial = 0.3125

4 0
3 years ago
Evaluate when a=-6 and y=4 2a-y
stepladder [879]
Hello!

we put the a and y values into the equation

2(-6) - 4

2 * -6 = -12

-12 - 4 = -16

The answer is -16

Hope this helps!
6 0
3 years ago
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