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mojhsa [17]
3 years ago
12

The average price of a movie ticket in the United States from 1980 to 2000 can be modeled by the expression 2.75+0.10x, where x

is the number of years since 1980.
Which part of the expression corresponds to the cost of movie tickets in 1980?
Mathematics
1 answer:
Trava [24]3 years ago
3 0

Answer:

2.75

Step-by-step explanation:

0.10 represents the rate at which prices have increased since 1980..

2.75 represents the price in 1980

This can be confirmed by inputting 0 as the value of x.

2.75+0.10(0) = 2.75

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Please help!!!! Can’t figure it out.
OleMash [197]

Answer:

A) x = 12

Step-by-step explanation:

if its a right angle? then the angle in total is 90 degrees,

subtract the 35 from 90 to get 55 degrees,

4x + 7 = 55 solve this

4x = 48

x = 12

8 0
2 years ago
How would i anser this select all the ratios equivalent to 4:6
Natali5045456 [20]
If we try to simplify the ratio or try to multiply both by any number, we will get the equivalent ratio


Like :

\frac{4}{6}  \\


Divide ( simplify ) by 2


\frac{ \frac{4}{2} }{ \frac{6}{2} }  \\  \\  \\  =  >  \frac{2}{3}




Or multiply by any number,



\frac{4}{6}  \\  \\  \\  =  >  \frac{4 \times 2}{6 \times 2}  \\  \\ \\    =  >  \frac{8}{12}





From the example, 2 / 3 and 8 / 12 are equivalent ratios to 4 / 6
6 0
3 years ago
What is 0.003 is 1/10 of
Svetach [21]
.003 is 1/10 of .03. To find it divide by 1/10
4 0
3 years ago
A county fair charges $9.00 for admission and $2.50 per ride. If Latisha spent $49 on admission and rides, how many rides did La
Hunter-Best [27]

Answer:

Latisha rode 16 rides

Step-by-step explanation:

Look at picture attached. Have a blessed night!

Just slope intercept formula (y=mx+b). X represents the number of rides so you will need to myltiply that by $2.50. $9 is a one time fee so that would be of the b of the equation. That all equals the total Latisha piaid, $49. Then solve like so.

4 0
2 years ago
Integration: How would I get to this answer?
Scrat [10]
Given that y attains a maximum at x=1, it follows that y'=0 at that same point. So integrating once gives

\displaystyle\int\frac{\mathrm d^2y}{\mathrm dx^2}\,\mathrm dx=\int-8x\,\mathrm dx
\dfrac{\mathrm dy}{\mathrm dx}=-4x^2+C_1
\implies -4(1)^2+C_1=0\implies C_1=4

and so the first derivative is y'=-4x^2+4.

Integrating again, you get

\displaystyle\int\frac{\mathrm dy}{\mathrm dx}\,\mathrm dx=\int(-4x^2+4)\,\mathrm dx
y=-\dfrac43x^3+4x+C_2

You know that this curve passes through the point (2, -1), which means when x=2, you have y=-1:

-1=-\dfrac43(2)^3+4(2)+C_2
\implies C_2=\dfrac53

and so

y=-\dfrac43x^3+4x+\dfrac53
7 0
3 years ago
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