6* 25 = 150 = (6*20= 120) + (6*5=30) Then Add 120+30= 150 so your answer is 5
Answer:
The interest is
<h2>$ 769.50</h2>
Step-by-step explanation:
Simple interest is given by

where
P is the principal
R is the rate
T is the time given
From the question
The principal / P = $ 5700
The rate / R = 4.5%
The time given / T = 3 years
So the interest is


We have the final answer as
I = $ 769.50
Hope this helps you
Answer:
C
Step-by-step explanation:
We want a line of best fit, which means we want to create a line that the data points will lie closest to.
One thing we can do is find the slope between the bottom-leftmost point and the top-rightmost point. This is because if we were to draw a line connecting these two, it will cut through the data quite well.
Those two points are (9, 15) and (16, 18), so the slope is change in y divided by the change in x:
(18 - 15) ÷ (16 - 9) = 3 ÷ 7 ≈ 0.4
Eliminate A and B.
Now we need to determine the y-intercept. This needs no calculations; simply look at the graph: there's no way a line cutting through the y-intercept point of (0, 18) will perfectly match the data points; instead it must be a y-intercept lower than 18. So, eliminate D.
The answer is C.
Answer:
The likelihood that the professor's socks matched his pants on both days is 0.5625
Step-by-step explanation:
Total no. of pair of socks = 24
No. of black pairs = 18
We are given that he selects one pair of socks on Monday and one on Tuesday. Since he has lots of clean socks in the drawer he does not do laundry.
So, It is a case of replacement
He always wears black pants.
We are supposed to find he likelihood that the professor's socks matched his pants on both days i.e. Black socks both days.
So ,Probability of wearing black socks on Monday = 
So ,Probability of wearing black socks on Tuesday =
So,the likelihood that the professor's socks matched his pants on both days = 
Hence the likelihood that the professor's socks matched his pants on both days is 0.5625