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2 years ago

PLEASE HELP

Mathematics

1 answer:

lozanna [386]2 years ago

4 0

It’s 46 hope that helps I don’t know how to put a picture of the work I did on here but I ta 46

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The length of an arc of a circle is 6.28 units, and the measure of the corresponding central angle is 1.12 radians. What is the

lorasvet [3.4K]

Hello,

$arc=\theta \ * R\\\\
R= \frac{6.28}{1.12} =5,607142857...$ ≈5.61

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3 years ago

Read 2 more answers

Find the length of EF

Lisa [10]

Answer:

Step-by-step explanation:

1. First, we need to set up an equation to find the value of x and then the length of EF.

2. We know that DG is equal to 33, so we can add all the three sections it's cut into altogether to get 33. Therefore, we get an equation of: $3x - 28 + 3x - 30 + x = 33$

3. (Solving for x)

Step 1: Simplify both sides of the equation.

$3x - 28 + 3x - 30 + x = 33$
$(3x+3x+x) + (-28-30)=33$
$7x - 58 = 33$

Step 2: Add 58 to both sides.

$7x - 58 + 58 = 33 + 58$
$7x = 91$

Step 3: Divide both sides by 7.

$\frac{7x}{7} = \frac{91}{7}$
$x = 13$

4. Now that we know x is equal to 13, we can plug that value in for the expression 3x - 30.

$3(13)-30$
$39 - 30$
$9$

Therefore, the length of EF is 9.

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2 years ago

Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent th

Tamiku [17]

Answer:

123 domestic stamps

89 foreign stamps

Step-by-step explanation:

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2 years ago

Make t the subject of 5(t − g) = 2t + 7

Alla [95]

Answer:

$5(t - g) = 2t + 7 \\ 5t - 5g = 2t + 7 \\ 5t - 2t = 7 + 5g \\ 3t = 7 + 5g \\ t = \frac{7 + 5g}{3}$

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2 years ago

Sample size: A researcher is trying to decide how many people to survey. Which of the following sample sizes will result in a co

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given that a researcher is trying to decide how many people to survey.

We have confidence intervals are intervals with middle value as the mean and on either side margin of error.

Confidence interval = Mean ± Margin of error

Thus confidence interval width depends on margin of error.

Margin of error = $Critical value *\frac{\sigma}{\sqrt{n} }$

Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.

Hence for small n we get wide intervals.

So if sample size = 300, the researcher will get wider confidence interval

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3 years ago