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Scilla [17]
3 years ago
10

BRAINLIEST!URGENT! Someone said that its B. but never gave me the steps. Can someone please show me how the answer is B?​

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0
So if never + rarely + often + always = 100%
when you take away never you get 68.7
always is 30.9
if you do 30.9/68.7 you get 45% so the answer is actually c
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What is the exact are of a square if the diameter is 14 cm?
riadik2000 [5.3K]

Answer:

196cm²

Step-by-step explanation:

because the area of something is the length times the width, and since this is a square it is 14 x 14, or 14², which is 196cm²

7 0
3 years ago
Can anyone help me with this problem
Kisachek [45]
In order to do this you first have to solve the parenthesis. Why because the pemdas tells you so, first parenthesis then exponents then multiplication then division then addition and then subtraction. So first subtract 7 from 9 to get (2)^-3 now multiply 2 3 times. -2*-2*-2 to get -8

Hope this helps
6 0
2 years ago
Here goes another question lol oops
Murrr4er [49]
Student 1 and 3.
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3 years ago
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What is the word form for the following fraction?<br><br> 8/4
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8 0
3 years ago
Find dy/dx by implicit differentiation.
kow [346]

dy/dx by implicit differentiation is cos(πx)/sin(πy)

<h3>How to find dy/dx by implicit differentiation?</h3>

Since we have the equation

(sin(πx) + cos(πy)⁸ = 17, to find dy/dx, we differentiate implicitly.

So, [(sin(πx) + cos(πy)⁸ = 17]

d[(sin(πx) + cos(πy)⁸]/dx = d17/dx

d[(sin(πx) + cos(πy)⁸]/dx = 0

Let sin(πx) + cos(πy) = u

So, du⁸/dx = 0

du⁸/du × du/dx = 0

Since,

  • du⁸/du = 8u⁷ and
  • du/dx = d[sin(πx) + cos(πy)]/dx

= dsin(πx)/dx + dcos(πy)/dx

= dsin(πx)/dx + (dcos(πy)/dy × dy/dx)

= πcos(πx) - πsin(πy) × dy/dx

So, du⁸/dx = 0

du⁸/du × du/dx = 0

8u⁷ × [ πcos(πx) - πsin(πy) × dy/dx] = 0

8[(sin(πx) + cos(πy)]⁷ ×  (πcos(πx) - πsin(πy) × dy/dx) = 0

Since 8[(sin(πx) + cos(πy)]⁷ ≠ 0

(πcos(πx) - πsin(πy) × dy/dx) = 0

πcos(πx) = πsin(πy) × dy/dx

dy/dx = πcos(πx)/πsin(πy)

dy/dx = cos(πx)/sin(πy)

So, dy/dx by implicit differentiation is cos(πx)/sin(πy)

Learn more about implicit differentiation here:

brainly.com/question/25081524

#SPJ1

6 0
1 year ago
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