Question

Use the quadratic formula to solve the equation -3x^2-x-3=0

Answer 1

Answer:

$x_{1=} \frac{-1+i\sqrt{35} }{6} \\\\x_{2=} \frac{-1-i\sqrt{35} }{6}$

Step-by-step explanation:

Using the quadratic formula:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

We will have two solutions:

$x_{1}\\ x_{2}$

-3x^2-x-3=0     a=-3    b=-1   c=-3

We have:

$x_{1}=\frac{1+\sqrt{-35} }{-6}\\\\x_{2}=\frac{1-\sqrt{-35} }{-6}$

we can write:

$x_{1}=\frac{-1+\sqrt{-35} }{6}\\\\x_{2}=\frac{-1-\sqrt{-35} }{6}$

The solutions are not real numbers.

So, we know: $i=\sqrt{-1}$

Finally we have:

$x_{1}=\frac{-1+i\sqrt{35} }{6}\\\\x_{2}=\frac{-1-i\sqrt{35} }{6}$