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iren2701 [21]
3 years ago
10

A solenoid of length 0.250 m and radius 0.0250 m is comprised of 440 turns of wire. Determine the magnitude of the magnetic fiel

d at the center of the solenoid when it carries a current of 12.0 A.

Physics
2 answers:
Bad White [126]3 years ago
6 0

Answer: 0.02654

Explanation:

in the attachment

Aliun [14]3 years ago
5 0

Answer:0.00265T

Explanation: magnetic field at the center of the solenoid(B)= magnetic permeability*number of turns(n)*current. But n=N/L=440/0.250=1760

Magnetic permeability =4*3.142*10^-7=0.0000001257T.m/A

B = 0.0000001257*10^-7*1760*12.0=0.00265T

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A metallic conductor has a resistivity of 35 × 10 −6 Ω⋅m. What is the resistance of a piece that is 20 m long and has a uniform
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Answer:

Therefore the resistance of the conductor is 175Ω

Explanation:

Resistance:

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The notation sign of resistance is R.

The unit of resistance is ohm (Ω).

Therefore,

R \propto l

and

R \propto \frac{1}{A}

\therefore R\propto \frac{l}{A}

\Rightarrow R=\rho \frac{l}{A}

ρ is the proportional constant.

It is also known as resistivity of that metal.

Given ρ=35×10⁻⁶Ω-m

l= 20 m

A= 4.0×10⁻⁶m²

\therefore R=35\times 10^{-6}\times \frac{20}{4.0\times 10^{-6}}

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A large helium filled balloon is used as the center piece for a graduation party. The balloon alone has a mass of 222 kg and it
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Where, \rho_{air} = density of air

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g = acceleration due to gravity

Put the value into the formula

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