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iren2701 [21]
4 years ago
10

A solenoid of length 0.250 m and radius 0.0250 m is comprised of 440 turns of wire. Determine the magnitude of the magnetic fiel

d at the center of the solenoid when it carries a current of 12.0 A.

Physics
2 answers:
Bad White [126]4 years ago
6 0

Answer: 0.02654

Explanation:

in the attachment

Aliun [14]4 years ago
5 0

Answer:0.00265T

Explanation: magnetic field at the center of the solenoid(B)= magnetic permeability*number of turns(n)*current. But n=N/L=440/0.250=1760

Magnetic permeability =4*3.142*10^-7=0.0000001257T.m/A

B = 0.0000001257*10^-7*1760*12.0=0.00265T

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gayaneshka [121]

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Explanation:

5 0
4 years ago
Can someone please help!!
frosja888 [35]

Answer:

Weight needed to balance the bar is 8.5N

Explanation:

Given the weight of the bar is 8N

The length of the bar is 5m

The weight of the bar will be uniformly distributed over the entire span. We will consider this as a point load acting in the middle of span length, which is at a distance of 2.5m from both ends.

Now applying momentum equation about balanced load we get, (see attachment)

\sum m_i=0\\2(m)+8(1)-8(0.5)-7(3)=0\\2m+8-4-21=0\\2m-17=0\\2m=17\\m=\frac{17}{2}=8.5\\So,\ m=8.5N

7 0
3 years ago
If he leaves the ramp with a speed of 31.0 m/s and has a speed of 29.5 m/s at the top of his trajectory, determine his maximum h
raketka [301]

Answer:

The maximum height reached is 4.63 m.

Explanation:

Given:

Initial speed of the man (u) = 31.0 m/s

Speed at the top of trajectory (u_x) = 29.5 m/s

Acceleration due to gravity (g) = 9.8 m/s²

When the man reaches the top of the trajectory, the vertical component of velocity becomes zero and hence only horizontal component of velocity acts on him.

Also, since there is no net force acting in the horizontal direction, the acceleration is zero in the horizontal direction from Newton's second law. Thus, the horizontal component of velocity always remains the same.

So, speed at the top of trajectory is nothing but the horizontal component of initial velocity.

Now, initial velocity can be rewritten in terms of its components as:

u^2=u_x^2+u_y^2

Where, u_x\ and\ u_y are the initial horizontal and vertical velocities of the man.

Now, plug in the given values and simplify. This gives,

(31.0)^2=(29.5)^2+u_y^2\\\\961=870.25+u_y^2\\\\u_y^2=961-870.25\\\\u_y^2=90.75\ m^2/s^2--------1

Now, we know that, for a projectile motion, the maximum height is given as:

H=\frac{u_y^2}{2g}

Plug in the value from equation (1) and 9.8 for 'g' to solve for 'H'. This gives,

H=\frac{90.75}{2\times 9.8}\\\\H=4.63\ m

Therefore, the maximum height reached is 4.63 m.

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An object can be at rest and still be in motion because the earth is always in motion.

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I had this question before can you show me the answer choices
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