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Verizon [17]
3 years ago
7

What is power when 3.2 A flows through an 18 ohm resistor?

Physics
1 answer:
vichka [17]3 years ago
4 0

To find the power formula on the electrical side you should have to know ohm's law of voltage that is V=I*R.

Here power formula is P=V*I.

Interms of resistance P=(IR)*I ==>I² R.

Here the power dissipated when 3.2 ampere of current flows through an 18-ohm resistor is

P=I² R ==>(3.2)² (18).

====>10.24(18)=184.32W.

W= Watts.

Watts is a unit of power.

Hope this helps

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wariber [46]

The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.

<u>Explanation:</u>

<u>Given</u>

t=?

d=6m

v=3*10^8 m/s

we  have,  v=d/t

here t=d/v

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The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.

<u></u>

6 0
3 years ago
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murzikaleks [220]

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