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2 years ago

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Mathematics

2 answers:

Ostrovityanka [42]2 years ago

6 0

Answer: B is the correct answer

Step-by-step explanation:

soldi70 [24.7K]2 years ago

3 0

Answer:

$x_1=1.23\\x_2=-0.40$

Step-by-step explanation:

Given a quadratic equation in the form $ax^2+bx+c=0$ , you can use the Quadratic formula to solve it. This is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

Then, you need to subtract $5x$ from both sides of the equation given:

$5x-5x=6x^2-3-5x\\0=6x^2-5x-3$

You can identify that:

$a=6\\b=-5\\c=-3$

Then, substituting values into the Quadratic formula, you get:

$x=\frac{-(-5)\±\sqrt{(-5)^2-4(6)(-3)}}{2(6)}$

$x_1=1.23\\x_2=-0.40$

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2 years ago

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V125BC [204]

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2 years ago

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vlada-n [284]

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2 years ago

If A(1,2), B(5,-4) and (-3,2) are the vertices of a triangle, which statement holds true?

Zigmanuir [339]

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The correct option is A.

<h3>What is a triangle?</h3>

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

The length of different sides are:

$AB = \sqrt{(5-1)^2+(-4-2)^2} = \sqrt{16+36} = \sqrt{52}\rm\ units$

$BC = \sqrt{(-3-5)^2+(2+4)^2} = \sqrt{64+36} = 10\rm\ units$

$AC = \sqrt{(2-2)^2+(-3-1)^2} = \sqrt{16} = 4\rm\ units$

Since the length of all the sides of the triangle is not equal it is a scalene triangle.

Hence, the correct option is A.

Learn more about Triangle:

brainly.com/question/2773823

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7 0

1 year ago

Read 2 more answers

I need help on this loll

Serhud [2]

Answer: The translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 )

is (x , y) → (x - 5 , y + 8)

Step-by-step explanation:

Let us revise the translation

If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y)

If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y)

If the point (x , y) translated vertically up by k units then its image is (x , y + k)

If the point (x , y) translated vertically down by k units then its image is (x , y - k)

(x , y) → (x ± h , y ± k) the right arrow symbol used to show the

translation from a point to its image

Example:

∵ P (0 , 0) → P' (1 , 2)

∴ The rule is (x , y) → (x + 1 , y + 2)

Let us find the translation rule that maps point D ( 7 , − 3 ) onto

point D' (2 , 5)

∵ Point (x , y) = (7 , -3)

∵ Its image after translation (x + h , y + k) = (2 , 5)

∴ x + h = 2

∵ x = 7

∴ 7 + h = 2

- Subtract 7 from both sides

∴ h = -5

∵ y + k = 5

∵ y = -3

∴ -3 + k = 5

- Add 3 to both sides

∴ k = 8

∴ The rule of translation is (x , y) → (x - 5 , y + 8)

The translation rule that maps point D ( 7 , − 3 ) onto point D ' ( 2 , 5 )

is (x , y) → (x - 5 , y + 8)

3 0

2 years ago