Question

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Answer 1

Answer: B is the correct answer

Step-by-step explanation:

Answer 2

Answer:

$x_1=1.23\\x_2=-0.40$

Step-by-step explanation:

Given a quadratic equation in the form $ax^2+bx+c=0$, you can use the Quadratic formula to solve it. This is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

Then, you need to subtract $5x$ from both sides of the equation given:

$5x-5x=6x^2-3-5x\\0=6x^2-5x-3$

You can identify that:

$a=6\\b=-5\\c=-3$

Then, substituting values into the Quadratic formula, you get:

 $x=\frac{-(-5)\±\sqrt{(-5)^2-4(6)(-3)}}{2(6)}$

$x_1=1.23\\x_2=-0.40$