Answer:
2 students from each 15 classrooms
Step-by-step explanation:
"The number of boys and girls is approximately equal" is probably the most random sample, that is if the whole topic of the publication is Lorrie and her experimenting endeavors. If that is not the subject, then "Lorrie wants to determine the average amount of time that students at her school spend on the computer each day" is the most strange and random
The probability of obtaining two blue marbles without replacement is equal to 0.15.
We are given that:
The number of yellow marbles = 3
Number of red marbles = 9
Number of Blue marbles = 8
Total marbles = 3 + 9 + 8
Total marbles = 20
Now, we have to calculate the probability of obtaining two blue marbles without replacement.
The probability will be:
P( obtaining two blue marbles without replacement ) = 8 / 20 × 7 / 19
P( obtaining two blue marbles without replacement ) = 56 / 380
P( obtaining two blue marbles without replacement ) = 0.15
Therefore, the probability of obtaining two blue marbles without replacement is equal to 0.15.
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In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
y=mx+B is the formula for finding the slop intercept
Hey again, you can use trigonometric ratios for this one. You are trying to find the side length opposite of angle G, when you have the adjacent side length value known. You can use TOA, or tan((opposite/adjacent)) . Tan(50) = x/10
X= 11.92 cm