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GREYUIT [131]
3 years ago
9

What is the equation of the circle graphed below? Use the caret ( ^ ) to enter any exponents; for example, write x2 as x^2.

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0
Equation of a circle in standard form:
(x-h)²+(y-k)²=r²
r=radius
(h,k) is the center.

In this case:
(h,k) =(0,0)   (h=0,k=0 )
r=4

Therefore:
(x-0)²+(y-0)²=4²
x²+y²=16

Answer: x²+y²=16
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Step-by-step explanation:

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3 years ago
What is the limit of the infinite series?
Ipatiy [6.2K]

Answer:

does not exist

Step-by-step explanation:

According to the divergence test, for an infinite series ∑ aₙ, the series diverges if lim(n→∞) aₙ ≠ 0.

Applying the divergence test here:

lim(n→∞) (3n⁵ / (4n⁵ + 1)) = 3/4

This is not 0, so the series does not converge, meaning the sum does not exist.

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3 years ago
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6 0
3 years ago
The sum of squares of two consecutive positive even integers is 52 more than their product. Find these numbers.
natulia [17]

Answer:

The first set of consecutive even integers equals (8 , 6)

The second set is ( - 8 and - 6) which also works.

Step-by-step explanation:

Equation

(x)^2 + (x + 2)^2 = (x)(x + 2) + 52            Remove the brackets on both sides

Solution

x^2 + x^2 + 4x + 4 = x^2 + 2x + 52        Collect the like terms on the left

2x^2+ 4x+ 4 = x^2 + 2x + 52                  Subtract right side from left

2x^2 - x^2 + 4x - 2x + 4 - 52  =  0          Collect the like terms

x^2 + 2x - 48 = 0                                     Factor

(x + 8)(x - 6) = 0

Answer

Try the one you know works.

x - 6 = 0

x = 6

Therefore the two integers are 6 and 8

6^2 + 8^2 = 100

6*8 + 52  = 100

So 6 and 8 is one set of  consecutive even numbers that works.    

========================

What about the other set.

x + 8 = 0

x = - 8

x and x + 2

- 8  and -8 + 2 = - 8, - 6

(- 8 )^2 + (- 6)^2 = 100

(-8)(-6) + 52 = 100

Both sets of consecutive numbers work.


5 0
3 years ago
Read 2 more answers
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