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GREYUIT [131]
3 years ago
9

What is the equation of the circle graphed below? Use the caret ( ^ ) to enter any exponents; for example, write x2 as x^2.

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0
Equation of a circle in standard form:
(x-h)²+(y-k)²=r²
r=radius
(h,k) is the center.

In this case:
(h,k) =(0,0)   (h=0,k=0 )
r=4

Therefore:
(x-0)²+(y-0)²=4²
x²+y²=16

Answer: x²+y²=16
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Operations with Radical Expressions
lisov135 [29]

Answer: 30\sqrt{11}

<u>Step-by-step explanation:</u>

  3\sqrt{50} * \sqrt{22}

= 3\sqrt{5*5*2} * \sqrt{2*11}

= 3\sqrt{5*5*2*2*11}

= 3*5*2\sqrt{11}

= 30\sqrt{11}

******************************************

Answer: 6\sqrt{30}

<u>Step-by-step explanation:</u>

  \sqrt{20} * \sqrt{3} * \sqrt{18}

= \sqrt{2*2*5} * \sqrt{3} * \sqrt{3*3*2}

= \sqrt{2*2*5*3*3*3*2}

= 2*3\sqrt{5*3*2}

= 6\sqrt{30}

********************************************

Answer: -\sqrt{5}

<u>Step-by-step explanation:</u>

  4\sqrt{20} - 3\sqrt{45}

= 4\sqrt{2*2*5} - 3\sqrt{3*3*5}

= 4*2\sqrt{5} - 3*3\sqrt{5}

= 8\sqrt{5} - 9\sqrt{5}

= -\sqrt{5}

********************************************

Answer: 4\sqrt{5}

<u>Step-by-step explanation:</u>

  2\sqrt{5} + 3\sqrt{5} - \sqrt{5}

= (2+3-1)\sqrt{5}

= 4\sqrt{5}

********************************************

Answer: 46\sqrt{2}

<u>Step-by-step explanation:</u>

  4\sqrt{32} + 6\sqrt{50}

= 4\sqrt{2*2*2*2*2} + 6\sqrt{2*5*5}

= 4*2*2\sqrt{2} + 6*5\sqrt{2}

= 16\sqrt{2} + 30\sqrt{2}

= 46\sqrt{2}





7 0
3 years ago
Find a point-slope form for the line that satisfies the stated conditions.
Yakvenalex [24]

Answer:

y=6x+41

Step-by-step explanation:

y-5=6(x+6)

y=6x+41

3 0
3 years ago
Is b - 12 = - 5; 17 solution
Pani-rosa [81]
No the answer to the solution would be 7
7 0
3 years ago
A trapezoid is shown. The lengths of the bases are 4 and 8. The height of the altitude is 4. What is the area of the trapezoid?
katrin [286]
It would be 24 units^2 because the middle is 16 and the two triangles are 4 each
3 0
2 years ago
Read 2 more answers
What is the equation of the axis of symmetry for the parabola y= 1/4(x+2)^2-7
Nezavi [6.7K]
Your answer is -2 as the axis of symmetry is at -b/2a. So if you were to expand the equation, you would get y= x^2/4 +x -6 where b is 1 and 2a is ½ . Therefore -1 / ½ gives you -2
7 0
3 years ago
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