Diagonals of an isosceles trapezoid are perpendicular to each other. The length of its leg is 26 cm. An altitude from the vertex
of an obtuse angle to the base divides the longer base into two parts, such that the shorter part is 10 cm long. What is the area of this trapezoid?
Please answer as soon as possible. Will be awarded 60 points!!!
Please answer as soon as possible. Will be awarded 60 points!!!
1 answer:
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Answer:
see explanation
Step-by-step explanation:
Using De Moivre's theorem
Given
[ 4(cos15° + isin15° ) ]³, then
= 4³ [ cos(3 × 15°) + isin(3 × 15°) ]
= 64 (cos45° + isin45° )
= 64 ( +
i )
= 64 ( (1 + i) )
= 32 (1 + i)
= 32 + 32
i
Answer:
Step-by-step explanation:
Hi there! I'm glad I was able to help you solve this equation!
Let's start by simplifying both sides of the equation. It's easier to solve it this way!
Distribute:
Combine 'like' terms:
Next, you'll want to add 36 to both sides of the equation.
Finally, divide both sides by .
I hope this helped you! Leave a comment below if you have any further questions! :)