Diagonals of an isosceles trapezoid are perpendicular to each other. The length of its leg is 26 cm. An altitude from the vertex
of an obtuse angle to the base divides the longer base into two parts, such that the shorter part is 10 cm long. What is the area of this trapezoid?
Please answer as soon as possible. Will be awarded 60 points!!!
Please answer as soon as possible. Will be awarded 60 points!!!
1 answer:
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if we divide 20 by 12, we get a quotient of 1, and a remainder of 8.
Answer:
Step-by-step explanation:
step 1
we have the points
(-1,0), (-2,0), and (0,2)
Plot the points
using a graphing tool
see the attached figure
The graph of a quadratic function must be a vertical parabola open upward
The vertex is a minimum
The quadratic function in general form is equal to
Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c
(0,2)
For x=0, y=2
substitute
(-1,0)
For x=-1, y=0
substitute
---->
----> equation A
(-2,0)
For x=-2, y=0
substitute
----> equation B
we have the system
----> equation A
----> equation B
substitute equation A in equation B
solve for b
Find the value of a
therefore
The quadratic function in general form is equal to
see the attached figure N 2 to better understand the problem
