Carson needed pencil and erasers, but the total amount can not be over 40. Pencils were $4 and erasers were 5$. How much pencils and erasers can he buy without spender over $80
Answer:
Length = 208 yards
Width = 54 yards
Step-by-step explanation:
Let the length of the field be "x" yards and the width be "y" yards. Its given that the length is 8 less than quadruple(4 times) the width. So x is 8 less than 4y. We can write this in equation as:
x = 4y - 8 Equation 1
Perimeter of the field is given to be 524 yards. Since, the field is rectangular, its perimeter is calculated as:
Perimeter = 2 (Length + Width)
Using the values, we get:
2(x + y) = 524 Equation 2
Substituting the value of x from Equation 1 into Equation 2, we get:
2(4y - 8 + y) = 524
2(5y - 8) = 524
5y - 8 = 524/2
5y - 8 = 262
5y = 262 + 8
5y = 270
y = 54 yards
Substituting the value of y in Equation 1, we get:
x = 4y - 8 = 4(54) - 8 = 208 yards
Thus, the length of the playing field is 208 yards and its width is 54 yards.
Hope that it will help you
Answer:
Step-by-step explanation:
Hemisphere Volume = (2/3) * PI * radius^3
sphere radius^3 = Hemisphere Volume / ((2/3) PI)
sphere radius^3 = 62,617 / 2.0943951024
sphere radius^3 = 29,897.4152147556
sphere radius = 31.0368674154
sphere diameter = 62.1 cm (rounded to nearest tenth of a centimeters)