Length of the box = 25 - 2x
Width of the box = 14 - 2x
Height of the box = x
a.) Volume of the box = x(25 - 2x)(14 - 2x) = x(350 - 50x - 28x + 4x^2) = 4x^3 - 78x^2 + 350x
Therefore, the function that models the volume of the box is V(x) = 4x^3 - 78x^2 + 350x
b.) 4x^3 - 78x^2 + 350x ≥ 240
4x^3 - 78x + 350x - 240 ≥ 0
x = 0.834, 5.438
The values of x for which the volume is greater than 240 in^3 is 0.834 ≤ x ≤ 5.438
c.) For maximum volume, dV/dx = 0
dV/dx = 12x^2 - 156x + 350 = 0
x = 2.882910931
Therefore, maximum volume = 4(2.882910931)^3 - 78(2.882910931)^2 +350(2.882910931) = 453.798 in^3
82 tens in the same thing as 820 because if you multiply 82 by 10 you get 820
Answer:
False
Step-by-step explanation:
STEP-BY-STEP SOLUTION:
Let's solve this problem step-by-step.
As posters are generally rectangular in shape, we will establish the formula for the area of a rectangle which we will be using as displayed below:
Area = height × width
Now let's find the area of the postwr using the above formula.
Height = 2 feet
Width = 0.7 feet
Area = height × width
Area = 2 × 0.7
Area = 1.4 square feet
ANSWER:
Therefore, the answer is:
The area of the poster is 1.4 square feet.
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Answer:
Step-by-step explanation:
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