Question

To sterilize a 48.0-g glass baby bottle, we must raise its temperature from 16.0°C to 94.0°C. How much heat transfer is required?

Answer 1

Answer:

3144.96 J

Explanation:

Heat transfer is,

$q=mc\Delta t$

As we know that the specific heat of the glass is,

$c=0.840J/g^{\circ}C$

Given that the mass of bottle is 48 g.

And the initial temperature is 16°C and the final temperature is 94°C.

Therefore,

$q=48\times 0.840(94^{\circ}-16^{\circ})\\q=48\times 0.840\times 78^{\circ}\\q=3144.96 J$