Yeah i think with a car or a plane:)
Answer:
The mass of the rule is 56.41 g
Explanation:
Given;
mass of the object suspended at zero mark, m₁ = 200 g
pivot of the uniform meter rule = 22 cm
Total length of meter rule = 100 cm
0 22cm 100cm
-------------------------Δ------------------------------------
↓ ↓
200g m₂
Apply principle of moment
(200 g)(22 cm - 0) = m₂(100 cm - 22 cm)
(200 g)(22 cm) = m₂(78 cm)
m₂ = (200 g)(22 cm) / (78 cm)
m₂ = 56.41 g
Therefore, the mass of the rule is 56.41 g
Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
by v=

we get
V₁=

V₁=10m/s
V₂=

V₂=9.8m/s
V₃=

V₃=9.61 m/s
V₄=

V₄=9.43 m/s
V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
Im pretty sure A-10 b-0 c-40
C. is the correct response.