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2 years ago

30 points please help a girl out!

Physics

1 answer:

ziro4ka [17]2 years ago

5 0

the answer would have to be A tell me if im wrong

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What is the de Broglie wavelength for a proton with energy 50 keV? Due to the limitations of Canvas, please give the wavelength

ad-work [718]

Answer:

1.2826 x 10^-13 m

Explanation:

$\lambda = \frac{h}{\sqrt{2 m K}}$

Here, k be the kinetic energy and m be the mass

K = 50 KeV = 50 x 1.6 x 10^-16 J = 80 x 10^-16 J

m = 1.67 x 10^-27 kg

$\lambda = \frac{6.63 \times 10^{-34}}{\sqrt{2 \times 1.67\times 10^{-27}\times 80\times 10^{-16}}}$

λ = 1.2826 x 10^-13 m

6 0

2 years ago

Describe two ways unbalanced forces help you in your day to<br> day life.

Alexxandr [17]

Answer:

we need unbalance force to lift objects
we need unbalance force to drag objects

6 0

2 years ago

The graph shows the number of beans eaten by a

il63 [147K]

Answer:

You didn't show a graph

Explanation:

6 0

3 years ago

Read 2 more answers

assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e

Dmitry [639]

Answer:

$9.3\cdot 10^{37}$

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

$P= \frac{E}{t}$

This means that the energy produced in the Sun each second (1 s), given the power $P=4.0\cdot 10^{26}W$ , is

$E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J$

Each p-p chain reaction produces an amount of energy of

$E_1 = 4.3\cdot 10^{-12} J$

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

$n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}$

3 0

3 years ago

When a nerve cell depolarizes, charge is transferred across the cell membrane, changing the potential difference. For a typical

laila [671]

Answer:

I = 18 x 10⁻⁹ A = 18 nA

Explanation:

The current is defined as the flow of charge per unit time. Therefore,

I = q/t

where,

I = Average Current passing through nerve cell

q = Total flow of charges through nerve cell

t = time period of flow of charges

Here, in our case:

I = ?

q = (9 pC)(1 x 10⁻¹² C/1 pC) = 9 x 10⁻¹² C

t = (0.5 ms)(1 x 10⁻³ s/1 ms) = 5 x 10⁻⁴ s

Therefore,

I = (9 x 10⁻¹² C)/(5 x 10⁻⁴ s)

6 0

2 years ago