(a) 5.66 m/s
The flow rate of the water in the pipe is given by

where
Q is the flow rate
A is the cross-sectional area of the pipe
v is the speed of the water
Here we have

the radius of the pipe is
r = 0.260 m
So the cross-sectional area is

So we can re-arrange the equation to find the speed of the water:

(b) 0.326 m
The flow rate along the pipe is conserved, so we can write:

where we have

and where  is the cross-sectional area of the pipe at the second point.
 is the cross-sectional area of the pipe at the second point.
Solving for A2,

And finally we can find the radius of the pipe at that point:

 
        
             
        
        
        
Answer:
a) acceleration
Explanation:
Acceleration is, by definition, the change of an object's velocity.
 
        
             
        
        
        
 is the equation that represents the Joule's law of heating.
 is the equation that represents the Joule's law of heating.
<h3>
Explanation:</h3>
Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to  
1. Square of Current (I²),
2. Resistance of the conductor (R)
3. Time for which current is passed (t)
Hence, Heat generated =  .....................(1)
 .....................(1)
By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).
 ...............................................(2)
 ...............................................(2)
From (2), Current (I) can be rewritten as 
 ........................................................(3)
 ........................................................(3)
Substituting (3) in (1), we get

 
        
             
        
        
        
Thermal. The tea is HOT and thermal energy is normally warmth