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Svet_ta [14]
2 years ago
6

The estimated regression equation is = 7.6 + .9x. what is the value of the standard error of the estimate (to 2 decimals)?

Mathematics
1 answer:
kupik [55]2 years ago
4 0
Any answer things? :/
You might be interested in
The sum of the areas of two circles is 80 pi
katovenus [111]
The area of a circle is A = πr^2. We let A1 And A2 the areas of the circles and r1 and r2 the radius of each, respectivley.

A1 + A2 = 80π
Substitute the formula for the area,
π(r1)^2 + π (r2)^2 = 80π

From the statement, we know that r2=2(r1).

<span>π(r1)^2 + π (2 x r1)^2 = 80π
</span>We can cancel π, we will have

5 x (r1)^2 = 80
Thus,

r1 = 4 and r2 = 8
5 0
3 years ago
If 3x−y=12, what is the value of <br>8x<br>2y
PSYCHO15rus [73]

Answer:

8x=32\\2y=-24

Step-by-step explanation:

When solving for 1 variable, set the other to 0 and solve.

3x-y(0)=12\\3x=12\\x=4\\4*8=32\\8x=32\\\\3(0)-y=12\\-y=12\\y=-12\\-12*2=-24\\2y=-24

8 0
2 years ago
Find the dimensions of the rectangle with area 289 square inches that has minimum perimeter, and then find the minimum perimeter
nalin [4]
 <span>To minimize the perimeter you should always have a square. 
sqrt(289) = 17 
The dimensions should be 17 X 17 

To see , try starting at length 1, and gradually increase the length. 
The height decreases at a faster rate than the length increases, up until you reach a square. 

Or if you want to use algebra, Say the width is 17-x 
Then the length is 289/(17-x) 

Now, this is bigger than 17+x, as shown here: 
289/(17-x) > 17+x 
289 > 289 - x^2 
which is true. 
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17 

Again, the dimensions should be a square. 17 X 17.</span>
4 0
3 years ago
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

4 0
3 years ago
Find the equation of the line that passes through the point of intersection of x + 2y = 9 and 4x -2y = -4 and the point of inter
Rudik [331]

Answer:

y=-6x+10

Step-by-step explanation:

The point of intersection of

x+2y=9...eqn1


and


4x-2y=-4...eqn2

is the solution of the two equations.


We add equation (1) and equation(2) to get,

x+4x+2y-2y=9+-4


\Rightarrow 5x=5


\Rightarrow x=1

We put x=1 into equation (1) to get,

1+2y=9

\Rightarrow 2y=9-1

\Rightarrow 2y=8

\Rightarrow y=4


Therefore the line passes through the point, (1,4).


The line also passes through the point of intersection of

3x-4y=14...eqn(3)

and

3x+7y=-8...eqn(4)

We subtract equation (3) from equation (4) to obtain,

3x-3x+7y--4y=-8-14


\Rightarrow 11y=-22

\Rightarrow y=-2


We substitute this value into equation (4) to get,

3x+7(-2)=-8


3x-14=-8


3x=-8+14


3x=6

x=2

The line also passes through

(2,-2)



The slope of the line is

slope=\frac{4--2}{1-2} =\frac{6}{-1}=-6


The equation of the line is

y+2=-6(x-2)

y+2=-6x+12


y=-6x+10 is the required equation





4 0
3 years ago
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